Java 8 Streams：获取非重复计数

Question

这是输入和输出的SQL版本：

     with tab1 as (

        select 1 as id from dual union all
        select 1 as id from dual union all
        select 2 as id from dual union all
        select 2 as id from dual union all
        select 5 as id from dual 
        )

    select id from tab1 group by id having count(id)=1;

Output is Id=5 and count is 1

由于5是不可重复的，如何使用JAVA 8流实现它？

我在下面尝试过，但显然给出了错误的结果

List<Integer> myList = new ArrayList<Integer>();
                myList.add(1);
                myList.add(1);
                myList.add(2);
                myList.add(2);
                myList.add(5);

                Long f =  myList.stream()
                          .distinct().count();

                System.out.println(f);

Answer 1

long result = myList.stream()
         .collect(Collectors.groupingBy(
                   Function.identity(),
                  Collectors.counting()))
         .entrySet()
         .stream()
         .filter(entry -> entry.getValue() == 1)
         .map(Entry::getKey)
         .count();

好吧，您将所有元素收集到Map<Integer, Long>，其中键是值本身，值是重复次数。后来我们流从产生的地图的条目集和filter只有那些项目，对具有计数1（这意味着他们不重复），以后我们map要Entry::getKey-让从列表中值和计数。