在ajax调用中访问函数外部变量的问题

Question

$.getJSON(“http://192.168.1.9:8983/solr/db/select/?wt=json&&start=0&rows=100&q="+query+"&json.wrf=?", function(result){
//$.each(result.response.docs, function(result){

                if(result.response.numFound==0)
                {


                $.ajax({
                    url: "http://192.168.1.9:8983/solr/db/select/?wt=json&&start=0&rows=100&q="+query+"&spellcheck=true&json.wrf=?",
                    async:false,
                    success: function(result){
                    $.each(result.spellcheck.suggestions, function(i,item){
                        newquery=item.suggestion;

                    });
                    }
                });
}

我得到我必须使ajax调用异步的问题。所以我确实喜欢上面的代码，但仍然无法在if块之外获取更新的newquery。它仍然显示newquery的旧值。请建议我在哪里做错了

编辑

$(document).ready(function(){
// This function get the search results from Solr server 
    $("#submit").click(function(){
        var query=getquerystring() ; //get the query string entered by user
        // get the JSON response from solr server 
        var newquery=query;

$.getJSON("http://192.168.1.9:8983/solr/db/select/?wt=json&&start=0&rows=100&q="+query+"&json.wrf=?", function(result){
            //$.each(result.response.docs, function(result){

            if(result.response.numFound==0)
                    {


                $.ajax({
                    url: "http://192.168.1.9:8983/solr/db/select/?wt=json&&start=0&rows=100&q="+query+"&spellcheck=true&json.wrf=?",
                    async:false,
                    dataType: 'json',

                    success: function(json){
                    $.each(json.spellcheck.suggestions, function(i,item){
                        newquery=item.suggestion;

                    });
                    }

                });

                }


    $.getJSON("http://192.168.1.9:8983/solr/db/select/?wt=json&&start=0&rows=20&q="+newquery+"&sort=price asc&hl=true&hl.fl=description&hl.usePhraseHighlighter=true&json.wrf=?", function(result){

现在，如果result.response.numFound == 0，我想在$getjosn（）中使用此更新的newquery，否则newquery将保留旧值

Answer 1

试试这个：

$(document).ready(function(){
    // This function get the search results from Solr server 
    $("#submit").click(function(){
        var query=getquerystring() ; //get the query string entered by user
        var newquery=query;
        $.getJSON("http://192.168.1.9:8983/solr/db/select/?wt=json&&start=0&rows=100&q="+query+"&json.wrf=?", function(result){
            if(result.response.numFound==0)
            {
                $.ajax({
                    url: "http://192.168.1.9:8983/solr/db/select/?wt=json&&start=0&rows=100&q="+query+"&spellcheck=true&json.wrf=?",
                    async:false,
                    dataType: 'json',
                    success: function(json){
                        $.each(json.spellcheck.suggestions, function(i,item){
                            newquery=item.suggestion;
                        }); 
                        $.getJSON("http://192.168.1.9:8983/solr/db/select/?wt=json&&start=0&rows=20&q="+newquery+"&sort=price asc&hl=true&hl.fl=description&hl.usePhraseHighlighter=true&json.wrf=?", function(result){
                    }

                    });
                }
            }else{

                $.getJSON("http://192.168.1.9:8983/solr/db/select/?wt=json&&start=0&rows=20&q="+newquery+"&sort=price asc&hl=true&hl.fl=description&hl.usePhraseHighlighter=true&json.wrf=?", function(result){

            }