使用swift4的iso8601日期json解码

Question

所以，我的json中有iso8601日期，看起来像“ 2016-06-07T17：20：00.000 + 02：00”

有没有办法使用swift4解析这些iso8601日期？我缺少明显的东西吗？

我尝试了以下操作，但是仅jsonShipA中的dateString“ 2016-06-07T17：20：00Z”是可解析的…。

import Foundation

struct Spaceship : Codable {
    var name: String
    var createdAt: Date
}

let jsonShipA = """
{
    "name": "Skyhopper",
    "createdAt": "2016-06-07T17:20:00Z"
}
"""

let jsonShipB = """
{
    "name": "Skyhopper",
    "createdAt": "2016-06-07T17:20:00.000+02:00"
}
"""

let decoder = JSONDecoder()
decoder.dateDecodingStrategy = .iso8601

let dataA = jsonShipA.data(using: .utf8)!
if let decodedShip = try? decoder.decode(Spaceship.self, from: dataA) {
    print("jsonShipA date = \(decodedShip.createdAt)")
} else {
    print("Failed to decode iso8601 date format from jsonShipA")
}

let dataB = jsonShipB.data(using: .utf8)!
if let decodedShip = try? decoder.decode(Spaceship.self, from: dataB) {
    print("jsonShipA date = \(decodedShip.createdAt)")
} else {
    print("Failed to decode iso8601 date format from jsonShipB")
}

游乐场的输出为：

jsonShipA date = 2016-06-07 17:20:00 +0000
Failed to decode iso8601 date format from jsonShipB

引发的错误是“预期日期字符串为ISO8601格式”。但是据我所知，日期“ 2016-06-07T17：20：00.000 +
02：00”是有效的ISO8601日期

Answer 1

您可以这样使用：

enum DateError: String, Error {
    case invalidDate
}

let decoder = JSONDecoder()

let formatter = DateFormatter()
formatter.calendar = Calendar(identifier: .iso8601)
formatter.locale = Locale(identifier: "en_US_POSIX")
formatter.timeZone = TimeZone(secondsFromGMT: 0)

decoder.dateDecodingStrategy = .custom({ (decoder) -> Date in
    let container = try decoder.singleValueContainer()
    let dateStr = try container.decode(String.self)

    formatter.dateFormat = "yyyy-MM-dd'T'HH:mm:ss.SSSXXXXX"
    if let date = formatter.date(from: dateStr) {
        return date
    }
    formatter.dateFormat = "yyyy-MM-dd'T'HH:mm:ssXXXXX"
    if let date = formatter.date(from: dateStr) {
        return date
    }
    throw DateError.invalidDate
})