将JSON转换为类似于Flutter中的android的POJO（对象）
蒋茂材
问题内容：
问题答案：
我只是想找到一种方法来将json响应（从REST
API）转换为POJO（在android中使用），这样我就可以将接收到的数据使用到我的应用程序中了，因为使用Map不会足够m接收有点复杂，包含3个级别的数组（数组内部的数组在数组内部的数组）。
我正在使用Dio库进行api调用，我可以成功进行API调用，并在控制台上毫无问题地打印数据。谁能协助我达成目标？
以下是我得到的答复。
{
"status": 200,
"message": "success",
"data": [
{
"menu": {
"megamenu_id": "55",
"language_id": "1",
"title": "Mobiles",
"description": "",
"submenu": [
{
"0": {
"info": {
"megamenu_id": "67",
"language_id": "1",
"title": "Mobile Phones",
"description": ""
}
},
"subsubmenu": [
{
"infosub": {
"megamenu_id": "68",
"language_id": "1",
"title": "Android Phones",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "69",
"language_id": "1",
"title": "Smart Phones",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "70",
"language_id": "1",
"title": "Windows Phones",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "72",
"language_id": "1",
"title": "Basic Phones",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "73",
"language_id": "1",
"title": "Latest Mobiles",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "74",
"language_id": "1",
"title": "Upcoming Mobiles",
"description": ""
}
}
]
},
{
"0": {
"info": {
"megamenu_id": "75",
"language_id": "1",
"title": "Brands",
"description": ""
}
},
"subsubmenu": [
{
"infosub": {
"megamenu_id": "76",
"language_id": "1",
"title": "Samsung",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "77",
"language_id": "1",
"title": "Apple",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "78",
"language_id": "1",
"title": "Redmi",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "79",
"language_id": "1",
"title": "Nokia",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "81",
"language_id": "1",
"title": "Sony",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "82",
"language_id": "1",
"title": "Micromax",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "83",
"language_id": "1",
"title": "HTC",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "84",
"language_id": "1",
"title": "Motorola",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "85",
"language_id": "1",
"title": "Oppo",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "86",
"language_id": "1",
"title": "Vivo",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "87",
"language_id": "1",
"title": "Honor",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "88",
"language_id": "1",
"title": "Oneplus",
"description": ""
}
}
]
},
{
"0": {
"info": {
"megamenu_id": "94",
"language_id": "1",
"title": "Mobile Accessories",
"description": ""
}
},
"subsubmenu": [
{
"infosub": {
"megamenu_id": "95",
"language_id": "1",
"title": "Bluetooth Headsets",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "96",
"language_id": "1",
"title": "Mobile Chargers",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "97",
"language_id": "1",
"title": "Mobiles Cases & Covers",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "98",
"language_id": "1",
"title": "Screen Protector",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "99",
"language_id": "1",
"title": "Mobile Batteries",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "100",
"language_id": "1",
"title": "Headphones & Headsets",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "101",
"language_id": "1",
"title": "Memory Cards",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "102",
"language_id": "1",
"title": "Power Banks",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "103",
"language_id": "1",
"title": "Stylus",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "104",
"language_id": "1",
"title": "Mobile Docks",
"description": ""
}
}
]
},
{
"0": {
"info": {
"megamenu_id": "107",
"language_id": "1",
"title": "Features",
"description": ""
}
},
"subsubmenu": [
{
"infosub": {
"megamenu_id": "108",
"language_id": "1",
"title": "Dual Sim Phones",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "111",
"language_id": "1",
"title": "4GB Ram Mobiles",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "112",
"language_id": "1",
"title": "Rear Camera [13 MP]",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "113",
"language_id": "1",
"title": "Screen Size [4.5 - 5.2 Inch]",
"description": ""
}
}
]
}
]
}
},
{
"menu": {
"megamenu_id": "168",
"language_id": "1",
"title": "Fashion",
"description": "",
"submenu": [
{
"0": {
"info": {
"megamenu_id": "169",
"language_id": "1",
"title": "Clothing",
"description": ""
}
},
"subsubmenu": [
{
"infosub": {
"megamenu_id": "170",
"language_id": "1",
"title": "T-Shirts",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "171",
"language_id": "1",
"title": "Shirts",
"description": ""
}
}
]
},
{
"0": {
"info": {
"megamenu_id": "178",
"language_id": "1",
"title": "Womens Clothing",
"description": ""
}
},
"subsubmenu": [
{
"infosub": {
"megamenu_id": "187",
"language_id": "1",
"title": "Night Wear",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "188",
"language_id": "1",
"title": "Tunics",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "189",
"language_id": "1",
"title": "Kurtis",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "190",
"language_id": "1",
"title": "Sarees",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "191",
"language_id": "1",
"title": "Lehengas",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "192",
"language_id": "1",
"title": "Swimming Suit",
"description": ""
}
}
]
},
{
"0": {
"info": {
"megamenu_id": "193",
"language_id": "1",
"title": "Men's Footwear",
"description": ""
}
},
"subsubmenu": [
{
"infosub": {
"megamenu_id": "194",
"language_id": "1",
"title": "Shoes",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "195",
"language_id": "1",
"title": "Sneakers",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "196",
"language_id": "1",
"title": "Sandals & Floaters",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "197",
"language_id": "1",
"title": "Slippers & Flip Flops",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "198",
"language_id": "1",
"title": "Loafers",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "199",
"language_id": "1",
"title": "Boots",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "200",
"language_id": "1",
"title": "Shoe Care",
"description": ""
}
}
]
},
{
"0": {
"info": {
"megamenu_id": "201",
"language_id": "1",
"title": "Women's Jewellery",
"description": ""
}
},
"subsubmenu": [
{
"infosub": {
"megamenu_id": "202",
"language_id": "1",
"title": "Earrings",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "203",
"language_id": "1",
"title": "Bangles",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "204",
"language_id": "1",
"title": "Bracelets",
"description": ""
}
},
{
"infosub": {
"megamenu_id": "205",
"language_id": "1",
"title": "Rings",
"description": ""
}
}
]
}
]
}
},
{
"menu": {
"megamenu_id": "220",
"language_id": "1",
"title": "Care",
"description": ""
}
},
{
"menu": {
"megamenu_id": "221",
"language_id": "1",
"title": "Offers",
"description": ""
}
},
{
"menu": {
"megamenu_id": "222",
"language_id": "1",
"title": "News",
"description": ""
}
}
]
}
问题答案：
因此，在尝试使用json_serializable库后，我想出了自己的解决方案，它根本不需要任何外部库，并且像一个魅力一样工作。这样，我必须编写更少的样板代码，我认为这是一种干净的方法。
这是制作模型的方法
class SideMenuRes {
final int status;
final String message;
final List<SideMenuDatum> sideMenuData;
SideMenuRes({this.status, this.message, this.sideMenuData});
factory SideMenuRes.fromJson(Map json) {
return SideMenuRes(
status: json['status'],
message: json['message'],
sideMenuData: json['status'] == 200 ? (json['data'] as List).map((i) => new
SideMenuDatum.fromJson(i)).toList() : null,
);
}
}
class SideMenuDatum {
final Menu menu;
SideMenuDatum({this.menu});
factory SideMenuDatum.fromJson(Map json) {
return SideMenuDatum(
menu: Menu.fromJson(json['menu']),
);
}
}
class Menu {
final String megamenu_id;
final String language_id;
final String title;
final String description;
final List<SubMenu> subMenu;
Menu({this.megamenu_id, this.language_id, this.title, this.description, this.subMenu});
factory Menu.fromJson(Map json) {
return Menu(
megamenu_id: json['megamenu_id'],
language_id: json['language_id'],
title: json['title'],
description: json['description'],
subMenu: json['submenu'] != null ? (json['submenu'] as List).map((i) => new SubMenu.fromJson(i)).toList() : null
);
}
}
class SubMenu {
final Zero zero;
final List<SubSubMenu> subSubMenu;
SubMenu({this.zero, this.subSubMenu});
factory SubMenu.fromJson(Map json) {
return SubMenu(
zero: Zero.fromJson(json['0']),
subSubMenu: (json['subsubmenu'] as List).map((i) => new SubSubMenu.fromJson(i)).toList()
);
}
}
class Zero {
final Info info;
Zero({this.info});
factory Zero.fromJson(Map json) {
return Zero(
info: Info.fromJson(json['info']),
);
}
}
class SubSubMenu {
final InfoSub infoSub;
SubSubMenu({this.infoSub});
factory SubSubMenu.fromJson(Map json) {
return SubSubMenu(
infoSub: InfoSub.fromJson(json['infosub'])
);
}
}
class InfoSub {
final String megamenu_id;
final String language_id;
final String title;
final String description;
InfoSub({this.megamenu_id, this.language_id, this.title, this.description});
factory InfoSub.fromJson(Map json) {
return InfoSub(
megamenu_id: json['megamenu_id'],
language_id: json['language_id'],
title: json['title'],
description: json['description']
);
}
}
class Info {
final String megamenu_id;
final String language_id;
final String title;
final String description;
Info({this.megamenu_id, this.language_id, this.title, this.description});
factory Info.fromJson(Map json) {
return Info(
megamenu_id: json['megamenu_id'],
language_id: json['language_id'],
title: json['title'],
description: json['description']
);
}
}
并这样称呼它
SubMenuRes subMenuRes = SubMenuRes.fromJson(response.data);
而已！
类似资料：
-
问题内容： 我正在将Jersey用于REST WS，并且得到的响应为JSON。 我想将此响应转换为POJO。怎么做 ？ 问题答案： 要在Java和JSON之间进行转换，有很多可供选择的API 。 您可以“手动”遍历JSON组件并提取值以填充Java对象，或者可以使用JSON到Java的绑定API来解决许多低级映射问题。
-
我想在我的JS项目中使用类似Java-POJO的类：只有私有字段，getters和setters。 我会在JSON字符串中转换我的类似Java-POJO的类，以将其发送到服务器。我不能使用JSON.stringify（myClass），因为这些字段是私有的。所以我认为使用这样的递归方法... ...但是在我花了很多时间写它之前，我想问你是否存在一种更好的方法来转换JSON中的Java-POJO类对
-
我尝试使用DTO到JSON（在JSON文件中写入）和JSON到DTO（从JSON文件中读取）作为常用方法（不同pojo写入/读取操作使用的通用方法） 为了作为通用方法使用，我使用返回类型作为对象。 在我的代码下面 提前道谢。
-
我有这样一个json： 所以它是一个包含名称数组的对象。对此，什么是等效的Pojo？ 但是我得到嵌套异常:
-
我正在尝试将JSON转换为POJO类。这个JSON是我从第三方REST API调用得到的，我想把它转换成POJO类。为此，我使用jackson databind jar，下面是我代码的一部分。 这里现在不是POJO类，我声明了Object类型的ModelObjcet变量，我的问题是我们是否需要在将JSON转换为POJO之前创建带有必填字段和getter setter方法的POJO类？ 如果是，那么
-
问题内容： 我正在用PHP开发Web应用程序， 我需要将许多对象作为JSON字符串从服务器传输，是否存在用于PHP的任何库，以将对象转换为JSON，并将JSON字符串转换为Objec，例如Java的Gson库。 问题答案： 这应该可以解决问题！ 这是一个例子 如果您希望输出为数组而不是对象，则传递给 有关json_encode（）的更多信息 另请参阅：json_decode（）