在python中将SQL表返回为JSON

Question

我在web.py中玩一个小型Web应用程序，并且正在设置一个URL以返回JSON对象。使用python将SQL表转换为JSON的最佳方法是什么？

Answer 1

就个人而言，我更喜欢使用SQLObject进行此类操作。我改编了一些必须快速完成的测试代码：

import simplejson

from sqlobject import *

# Replace this with the URI for your actual database
connection = connectionForURI('sqlite:/:memory:')
sqlhub.processConnection = connection

# This defines the columns for your database table. See SQLObject docs for how it
# does its conversions for class attributes <-> database columns (underscores to camel
# case, generally)

class Song(SQLObject):

    name = StringCol()
    artist = StringCol()
    album = StringCol()

# Create fake data for demo - this is not needed for the real thing
def MakeFakeDB():
    Song.createTable()
    s1 = Song(name="B Song",
              artist="Artist1",
              album="Album1")
    s2 = Song(name="A Song",
              artist="Artist2",
              album="Album2")

def Main():
    # This is an iterable, not a list
    all_songs = Song.select().orderBy(Song.q.name)

    songs_as_dict = []

    for song in all_songs:
        song_as_dict = {
            'name' : song.name,
            'artist' : song.artist,
            'album' : song.album}
        songs_as_dict.append(song_as_dict)

    print simplejson.dumps(songs_as_dict)


if __name__ == "__main__":
    MakeFakeDB()
    Main()