按索引列表分割字符串

Question

我想按索引列表来分割字符串，其中分割段以一个索引开始，然后在下一个索引之前结束。

例：

s = 'long string that I want to split up'
indices = [0,5,12,17]
parts = [s[index:] for index in indices]
for part in parts:
    print part

这将返回：

长字符串，我想分手
的字符串，我想分手了
，我想分手
我想分手

我试图得到：

长
串
的是
我要分手

Answer 1

s = 'long string that I want to split up'
indices = [0,5,12,17]
parts = [s[i:j] for i,j in zip(indices, indices[1:]+[None])]

退货

['long ', 'string ', 'that ', 'I want to split up']

您可以使用以下命令进行打印：

print '\n'.join(parts)

另一种可能性（不复制indices）是：

s = 'long string that I want to split up'
indices = [0,5,12,17]
indices.append(None)
parts = [s[indices[i]:indices[i+1]] for i in xrange(len(indices)-1)]