我有这样的UPSERT操作:
INSERT INTO people (SELECT * FROM people_update)
ON CONFLICT (name,surname)
DO UPDATE SET age = EXCLUDED.age , street = EXCLUDED.street , city = EXCLUDED.city , postal = EXCLUDED.postal
WHERE
(people.age,people.street,people.city,people.postal) IS DISTINCT FROM (EXCLUDED.age,EXCLUDED.street,EXCLUDED.city,EXCLUDED.postal)
RETURNING case when xmax::text::int > 0 then 'updated' else 'inserted' end,name,surname,age,street,city,postal;
(name,surname)
是一个复合主键,与“ people”表相比,“ people_update”表包含其他行和已更改的行。
我的问题是:有没有办法将查询的插入行和更新行作为返回行?
编辑:我通过添加一个RETURNING
子句中途解决了问题,但我也想在我的返回值中获取旧值。
如果将布尔更新的列添加到people
表中:
ALTER TABLE people ADD COLUMN updated bool DEFAULT FALSE;
那么您可以通过updated = TRUE
在DO UPDATE SET
子句中进行设置来标识更新的行:
INSERT INTO people (SELECT * FROM people_update)
ON CONFLICT (name,surname)
DO UPDATE SET age = EXCLUDED.age , street = EXCLUDED.street , city = EXCLUDED.city
, postal = EXCLUDED.postal
, updated = TRUE
WHERE
(people.age,people.street,people.city,people.postal) IS DISTINCT FROM
(EXCLUDED.age,EXCLUDED.street,EXCLUDED.city,EXCLUDED.postal)
RETURNING *;
例如,
CREATE TABLE test.people (
name text
, surname text
, age float
, street text
, city text
, postal int
);
CREATE UNIQUE INDEX people_idx on people (name, surname);
ALTER TABLE people ADD COLUMN updated bool;
ALTER TABLE people ADD COLUMN prior_age float;
ALTER TABLE people ADD COLUMN prior_street text;
ALTER TABLE people ADD COLUMN prior_city text;
ALTER TABLE people ADD COLUMN prior_postal int;
INSERT INTO people (name, surname, age, street, city, postal) VALUES
('Sancho', 'Panza', 414, '1 Manchego', 'Barcelona', 01605)
, ('Oliver', 'Twist', 182, '2 Stilton', 'London', 01837)
, ('Quasi', 'Modo', 188, $$3 Rue d'Arcole$$, 'Paris' , 01831 )
;
CREATE TABLE test.people_update (
name text
, surname text
, age float
, street text
, city text
, postal int
);
INSERT INTO people_update (name, surname, age, street, city, postal) VALUES
('Sancho', 'Panza', 4140, '10 Idiazabal', 'Montserrat', 16050)
, ('Quasi', 'Modo', 1880, $$30 Champs Elys茅e$$ , 'Paris', 18310 )
, ('Pinocchio', 'Geppetto', 1380, '40 Nerbone', 'Florence', 18810)
;
INSERT INTO people (SELECT * FROM people_update)
ON CONFLICT (name,surname)
DO UPDATE SET
updated = TRUE
, prior_age = (CASE WHEN people.age = EXCLUDED.age THEN NULL ELSE people.age END)
, prior_street = (CASE WHEN people.street = EXCLUDED.street THEN NULL ELSE people.street END)
, prior_city = (CASE WHEN people.city = EXCLUDED.city THEN NULL ELSE people.city END)
, prior_postal = (CASE WHEN people.postal = EXCLUDED.postal THEN NULL ELSE people.postal END)
, age = EXCLUDED.age
, street = EXCLUDED.street
, city = EXCLUDED.city
, postal = EXCLUDED.postal
WHERE
(people.age,people.street,people.city,people.postal) IS DISTINCT FROM
(EXCLUDED.age,EXCLUDED.street,EXCLUDED.city,EXCLUDED.postal)
RETURNING *;
产量
| name | surname | age | street | city | postal | updated | prior_age | prior_street | prior_city | prior_postal |
|------------+----------+------+------------------+------------+--------+---------+-----------+----------------+------------+--------------|
| Sancho | Panza | 4140 | 10 Idiazabal | Montserrat | 16050 | t | 414 | 1 Manchego | Barcelona | 1605 |
| Quasi | Modo | 1880 | 30 Champs Elys茅e | Paris | 18310 | t | 188 | 3 Rue d'Arcole | | 1831 |
| Pinocchio | Geppetto | 1380 | 40 Nerbone | Florence | 18810 | f | | | | |
该updated
列显示('Sancho', 'Panza')
和('Quasi', 'Modo')
行已更新,并且 ('Pinocchio', 'Geppetto')
是新插入的。
但现在我也需要知道: 插入了多少行 由于现有而更新了多少行 由于约束无法插入多少行 如果最后一行没有遵守约束,那么以前插入/更新的行是否会保留在数据库中?
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