没有路径前缀的Django i18n默认语言

Question

我有一个要移植到Django 1.4的现有多语言Django应用程序。I18n支持目前基于一些丑陋的技巧，我想使其使用Django的内置i18n模块。

一个约束是我不想更改已经存在的URL。这个网站已经活跃了一段时间，并且有一些我不想破坏或重定向的外部链接。url方案的工作原理如下：英语内容位于网站的根目录，而其他语言则在域名中使用前缀：

英文网址：

/
/articles/
/suggestions/

西班牙语网址：

/es/
/es/articulos/
/es/sugerencias/

我已经将翻译后的页面与Django 1.4的i18n模块一起使用，但是它确实非常希望将所有英文url放在/ en /下。我尝试了几种不同的技巧，包括为英语版本定义了非国际化的URL：

def build(callback):
  return callback('',
    url(_(r'^$'), home.index, name="home"),
    url(_(r'^articles/$'), content.article_list, name='article_list'),
    url(_(r'^suggestions/$'), suggestions.suggestions, name='suggestions'),
  )

urlpatterns = build(patterns)
urlpatterns += build(i18n_patterns)

这样可以正确解析网址，但是{％url％}标签无法进行反向解析。

Answer 1

请看下面的答案，Django 1.10本身支持它

我遇到了这个问题并以这种方式解决了：

• 创建了一个i18n_patterns不加前缀网站主要语言（在中定义settings.LANGUAGE_CODE）的替代方法。

• 创建了仅使用URL前缀语言来激活当前语言的备用中间件。

使用此技术我没有看到任何副作用。

代码：

# coding: utf-8
"""
Cauê Thenório - cauelt(at)gmail.com

This snippet makes Django do not create URL languages prefix (i.e. /en/)
for the default language (settings.LANGUAGE_CODE).

It also provides a middleware that activates the language based only on the URL.
This middleware ignores user session data, cookie and 'Accept-Language' HTTP header.

Your urls will be like:

In your default language (english in example):

    /contact
    /news
    /articles

In another languages (portuguese in example):

    /pt/contato
    /pt/noticias
    /pt/artigos

To use it, use the 'simple_i18n_patterns' instead the 'i18n_patterns'
in your urls.py:

    from this_sinppet import simple_i18n_patterns as i18n_patterns

And use the 'SimpleLocaleMiddleware' instead the Django's 'LocaleMiddleware'
in your settings.py:

    MIDDLEWARE_CLASSES = (
    ...
        'this_snippet.SimpleLocaleMiddleware'
    ...
    )

Works on Django >=1.4
"""

import re

from django.conf import settings
from django.conf.urls import patterns
from django.core.urlresolvers import LocaleRegexURLResolver
from django.middleware.locale import LocaleMiddleware
from django.utils.translation import get_language, get_language_from_path
from django.utils import translation


class SimpleLocaleMiddleware(LocaleMiddleware):

    def process_request(self, request):

        if self.is_language_prefix_patterns_used():
            lang_code = (get_language_from_path(request.path_info) or
                         settings.LANGUAGE_CODE)

            translation.activate(lang_code)
            request.LANGUAGE_CODE = translation.get_language()


class NoPrefixLocaleRegexURLResolver(LocaleRegexURLResolver):

    @property
    def regex(self):
        language_code = get_language()

        if language_code not in self._regex_dict:
            regex_compiled = (re.compile('', re.UNICODE)
                              if language_code == settings.LANGUAGE_CODE
                              else re.compile('^%s/' % language_code, re.UNICODE))

            self._regex_dict[language_code] = regex_compiled
        return self._regex_dict[language_code]


def simple_i18n_patterns(prefix, *args):
    """
    Adds the language code prefix to every URL pattern within this
    function, when the language not is the main language.
    This may only be used in the root URLconf, not in an included URLconf.

    """
    pattern_list = patterns(prefix, *args)
    if not settings.USE_I18N:
        return pattern_list
    return [NoPrefixLocaleRegexURLResolver(pattern_list)]