我有三个查询结果。
查询1:
SELECT DISTINCT employeeid, work.clientid, ROUND ((CAST (AVG(current_lawn_price) AS numeric) / CAST (AVG((((EXTRACT(HOUR FROM job_finish)*60) + EXTRACT(MIN FROM job_finish))) - ((EXTRACT(HOUR FROM job_start)*60) + EXTRACT(MIN FROM job_start))) AS numeric)) / 1, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 1 AND workid < 557 AND workid > 188
GROUP BY employeeid, clientid ORDER BY clientid ASC;
employeeid | clientid | under_over_1
------------+----------+--------------
1 | 3 | 0.54
1 | 4 | 0.47
1 | 6 | 0.45
1 | 7 | 0.59
. | . | .
. | . | .
查询2:
SELECT DISTINCT employeeid, work.clientid, ROUND ((CAST (AVG(current_lawn_price) AS numeric) / CAST (AVG((((EXTRACT(HOUR FROM job_finish)*60) + EXTRACT(MIN FROM job_finish))) - ((EXTRACT(HOUR FROM job_start)*60) + EXTRACT(MIN FROM job_start))) AS numeric)) / 1.31666666666667, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 2
GROUP BY employeeid, clientid ORDER BY clientid ASC;
employeeid | clientid | under_over_1
------------+----------+--------------
2 | 2 | 1.01
2 | 3 | 0.21
2 | 4 | 0.71
2 | 6 | 0.68
. | . | .
. | . | .
查询:3
SELECT DISTINCT employeeid, work.clientid, ROUND ((CAST (AVG(current_lawn_price) AS numeric) / CAST (AVG((((EXTRACT(HOUR FROM job_finish)*60) + EXTRACT(MIN FROM job_finish))) - ((EXTRACT(HOUR FROM job_start)*60) + EXTRACT(MIN FROM job_start))) AS numeric)) / 1.31666666666667, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 3
GROUP BY employeeid, clientid ORDER BY clientid ASC;
employeeid | clientid | under_over_1
------------+----------+--------------
3 | 4 | 0.70
3 | 6 | 0.54
3 | 7 | 1.03
3 | 11 | 0.74
. | . | .
. | . | .
我想输出一个表,其中包含所有三个查询的结果,例如(很抱歉,但我必须在这里写更多内容,以便我可以提交此帖子。我希望这足够;-)):
employeeid | clientid | under_over_1
------------+----------+--------------
1 | 3 | 0.54
1 | 4 | 0.47
1 | 6 | 0.45
1 | 7 | 0.59
. | . | .
. | . | .
2 | 2 | 1.01
2 | 3 | 0.21
2 | 4 | 0.71
2 | 6 | 0.68
. | . | .
. | . | .
3 | 4 | 0.70
3 | 6 | 0.54
3 | 7 | 1.03
3 | 11 | 0.74
. | . | .
. | . | .
我尝试UNION ALL
了
SELECT DISTINCT employeeid, work.clientid, ROUND ((CAST (AVG(current_lawn_price) AS numeric) / CAST (AVG((((EXTRACT(HOUR FROM job_finish)*60) + EXTRACT(MIN FROM job_finish))) - ((EXTRACT(HOUR FROM job_start)*60) + EXTRACT(MIN FROM job_start))) AS numeric)) / 1, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 1 AND workid < 557 AND workid > 188
GROUP BY employeeid, clientid ORDER BY clientid ASC
UNION ALL
SELECT DISTINCT employeeid, work.clientid, ROUND ((CAST (AVG(current_lawn_price) AS numeric) / CAST (AVG((((EXTRACT(HOUR FROM job_finish)*60) + EXTRACT(MIN FROM job_finish))) - ((EXTRACT(HOUR FROM job_start)*60) + EXTRACT(MIN FROM job_start))) AS numeric)) / 1.31666666666667, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 3
GROUP BY employeeid, clientid ORDER BY clientid ASC
UNION ALL
SELECT DISTINCT employeeid, work.clientid, ROUND ((CAST (AVG(current_lawn_price) AS numeric) / CAST (AVG((((EXTRACT(HOUR FROM job_finish)*60) + EXTRACT(MIN FROM job_finish))) - ((EXTRACT(HOUR FROM job_start)*60) + EXTRACT(MIN FROM job_start))) AS numeric)) / 1.31666666666667, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 2
GROUP BY employeeid, clientid ORDER BY clientid ASC;
但是,出现以下错误:
ERROR: syntax error at or near "UNION" LINE 7: UNION ALL
我不确定为什么这是错误的,或者UNION ALL
在这里是否正确的方法。有人知道吗?
导致错误的直接原因是引用手册:
(
ORDER BY
并且LIMIT
可以连接到如果一个子表达式 括在括号中
。如果没有括号,这些条款将被视为适用于的结果UNION
,而不是它的右手输入表达式。)
大胆强调我的。
因此,按照@wilx的建议,将每个SELECT
括号括起来即可解决 该问题 。
但是还有更多。
SELECT employeeid, work.clientid -- no DISTINCT
, ROUND ((AVG(current_lawn_price)
/ AVG(extract(epoch FROM job_finish - job_start)))::numeric / 79, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE (employeeid IN (1, 2) OR
employeeid = 3
AND workid < 557
AND workid > 188)
GROUP BY employeeid, clientid
ORDER BY CASE employeeid
WHEN 1 THEN 1
WHEN 2 THEN 3
WHEN 3 THEN 2
END
, clientid;
合并3个SELECT
查询。
删除冗余的DISTINCT
。之后那是昂贵的无人值守GROUP BY
。
与其从开始时间戳和结束时间戳等中提取小时和分钟,不如interval
通过简单的减法(使用timestamp
或time
值类似)来计算并从中提取epoch
。给您秒数。除以60,您得到的分钟数要快得多。
79 是 _ 60 * 1.31666666666667_ 的结果。
有关提取epoch
的手册:
对于
timestamp with time zone
值,是自1970-01-01 00:00:00
UTC以来的秒数(可以为负);对于date
和timestamp
值,自当地时间1970-01-01 00:00:00以来的秒数;
对于interval
值,间隔中的总秒数
大胆强调我的。
由于此删除UNION ALL
,不再需要在顶部提到的括号。
该CASE
表达式弥补了混合顺序employeeid
,如提供的粘滞位。
如果由于某种原因您不能或不会合并三个原始SELECT
查询,请执行以下操作:
( -- parentheses required
SELECT employeeid, work.clientid -- no DISTINCT !
, ROUND ((AVG(current_lawn_price)
/ AVG(extract(epoch FROM job_finish - job_start)))::numeric / 79, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 1
AND workid < 557
AND workid > 188
GROUP BY clientid -- no need to GROUP BY employeeid while filtering single value
ORDER BY clientid
)
UNION ALL
(
SELECT employeeid, work.clientid
, ROUND ((AVG(current_lawn_price)
/ AVG(extract(epoch FROM job_finish - job_start)))::numeric / 79, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 3
GROUP BY clientid
ORDER BY clientid
)
UNION ALL
(
SELECT employeeid, work.clientid
, ROUND ((AVG(current_lawn_price)
/ AVG(extract(epoch FROM job_finish - job_start)))::numeric / 79, 2) AS under_over_1
FROM work
JOIN timesheet USING (date_linkid)
JOIN client USING (clientid)
WHERE employeeid = 2
GROUP BY clientid
ORDER BY clientid
);
-- no outer ORDER BY required
保持ORDER BY
每个SELECT
并添加括号来解决语法。UNION ALL
(与相对UNION
)只是附加结果,以保持单个SELECT
s的顺序。这应该是 _ 便宜 比订购整套 _之后 UNION ALL
。而且您确实想继续SELECT
按原样使用单个查询…
上面的大多数其他建议也适用。
撇开: 养成使用表别名和对连接多个表的查询中的所有列进行表限定的习惯。对以后的更改更强大,并且更易于阅读/调试。
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