JPA选择计数不同

Question

我需要一个相对简单的查询，但是JPA使其很难创建。

SQL变量如下所示：

SELECT COUNT(DISTINCT OrderID) AS DistinctOrders FROM Orders WHERE CustomerID=7;

[编辑：OrderID不是主键。表格中可以有更多等于的OrderId]

我需要设置CustomerID一个传递给我的方法的变量。

我找到了文档，CriteriaQuery distinct()但似乎无法将它们全部包装在一起。

这是我到目前为止的内容：

CriteriaBuilder cb = this.em.getCriteriaBuilder();
CriteriaQuery<Order> c = cb.createQuery( Order.class );
Root<Order> order = c.from( Order.class );
Path<String> customerID = order.get( "customerID" );
c.where( cb.equal( customerID, theId ) );

Answer 1

CriteriaBuilder cb = this.em.getCriteriaBuilder();
CriteriaQuery<Long> c = cb.createQuery(Long.class);//the query returns a long, and not Orders
Root<Order> order = c.from( Order.class );
//c.select(cb.countDistinct(order));//and this is the code you were looking for
c.select(cb.countDistinct(order.get("orderID")));//for counting distinct fields other than the primary key
Path<String> customerID = order.get( "customerID" );
c.where( cb.equal( customerID, theId ) );