从这样的表中检索层次结构

Question

我将MySql与PHP结合使用，并将所有数据存储在这样的表中：

"id"    "name"         "description"               "level"  "parent"    "country"   "maxLevel"
"1"     "Kitchenware"   "Kitchenware description"   "1"       "0"         "US"        "0"
"2"     "Knives"        "All our knives"            "2"       "1"         "US"        "0"
"3"     "Butter Knives" "All Butter Knives"         "3"       "2"         "US"        "0"
"4"     "Cut em all"    "Cut em all"                "4"       "3"         "US"        "0"
"5"     "Cull em all"   "Cull em all"               "4"       "3"         "US"        "0"
"6"     "Smear em all"  "Smear em all"              "4"       "3"         "US"        "0"
"7"     "Meat Knives"   "All Meat Knives"           "3"       "2"         "US"        "0"
"8"     "Cut em meat"   "Cut em meat"               "4"       "7"         "US"        "0"
"9"     "Cull em meat"  "Cull em meat"              "4"       "7"         "US"        "0"
"10"    "Smear em meat" "Smear em meat"             "4"       "7"         "US"        "0"

由此，如果我有例如：id = 10，sql将如何显示项目的层次结构？

因此，对于id = 10，层次结构为：

Kitchenware > Knives > Meat Knives > Smear em meat

对于id = 7，层次结构为：

Kitchenware > Knives > Meat Knives

对于id = 4，层次结构为

Kitchenware > Knives > Butter Knives > Cut em all

等等。任何想法如何构造SQL来实现这一目标？

Answer 1

试试这个存储过程

CREATE PROCEDURE updatePath(in itemId int)
BEGIN
    DECLARE cnt int default 0;
    CREATE temporary table tmpTable 
    (
       `id` int, `name` varchar(15), `parent` int, path varchar(500)  
     )engine=memory select id, name, parent, name AS 'Path' from tbl where id = itemId;
    select parent into cnt from tmpTable;

    while cnt <> 0 do
       Update tmpTable tt, tbl t set tt.parent = t.parent, 
              tt.path = concat(t.name, ' > ', tt.path)
       WHERE tt.parent = t.id;
       select parent into cnt from tmpTable;
    end while;
    select * from tmpTable;
    drop table tmpTable;
END//

查询1 ：

call updatePath(10)

SQL FIDDLE ：

| ID |            NAME | PARENT |                                                       PATH |
----------------------------------------------------------------------------------------------
| 10 | "Smear em meat" |      0 | "Kitchenware" > "Knives" > "Meat Knives" > "Smear em meat" |

希望这可以帮助