如何加快python的'turtle'函数并最终使其停止冻结

Question

我已经用python编写了一个乌龟程序，但是有两个问题。

1. 对于较大的数字来说，速度太慢了，我想知道如何加快乌龟的速度。
2. 完成并单击时冻结，表示“未响应”

到目前为止，这是我的代码：

import turtle

#Takes user input to decide how many squares are needed
f=int(input("How many squares do you want?"))
c=int(input("What colour would you like? red = 1, blue = 2 and green =3"))
n=int(input("What background colour would you like? red = 1, blue = 2 and green =3"))

i=1

x=65

#Draws the desired number of squares.
while i < f:
    i=i+1
    x=x*1.05
    print ("minimise this window ASAP")
    if c==1:
        turtle.pencolor("red")
    elif c==2:
        turtle.pencolor("blue")
    elif c==3:
        turtle.pencolor("green")
    else:
        turtle.pencolor("black")
    if n==1:
        turtle.fillcolor("red")
    elif n==2:
        turtle.fillcolor("blue")
    elif n==3:
        turtle.fillcolor("green")
    else:
        turtle.fillcolor("white")
    turtle.bk(x)
    turtle.rt(90)
    turtle.bk(x)
    turtle.rt(90)
    turtle.bk(x)
    turtle.rt(90)
    turtle.bk(x)
    turtle.rt(90)
    turtle.up()
    turtle.rt(9)
    turtle.down()

顺便说一句：我使用的是3.2版！

Answer 1

1. 设置turtle.speed()到fastest。
2. 使用该turtle.mainloop()功能无需刷新屏幕即可进行工作。
3. 禁用屏幕刷新，turtle.tracer(0, 0)然后在最后做turtle.update()