In computer science, a heap is a specialized tree-based data structure that satisfies the heap property: if P is a parent node of C, then the key (the value) of P is either greater than or equal to (in a max heap) or less than or equal to (in a min heap) the key of C. A common implementation of a heap is the binary heap, in which the tree is a complete binary tree. (Quoted from Wikipedia at https://en.wikipedia.org/wiki/Heap_(data_structure))
Your job is to tell if a given complete binary tree is a heap.
Each input file contains one test case. For each case, the first line gives two positive integers: M (≤ 100), the number of trees to be tested; and N (1 < N ≤ 1,000), the number of keys in each tree, respectively. Then M lines follow, each contains N distinct integer keys (all in the range of int), which gives the level order traversal sequence of a complete binary tree.
For each given tree, print in a line Max Heap
if it is a max heap, or Min Heap
for a min heap, or Not Heap
if it is not a heap at all. Then in the next line print the tree's postorder traversal sequence. All the numbers are separated by a space, and there must no extra space at the beginning or the end of the line.
3 8
98 72 86 60 65 12 23 50
8 38 25 58 52 82 70 60
10 28 15 12 34 9 8 56
Max Heap
50 60 65 72 12 23 86 98
Min Heap
60 58 52 38 82 70 25 8
Not Heap
56 12 34 28 9 8 15 10
思路:将n个值存放到heap数组,对树进行遍历将从跟到所有叶子节点的路径存放到二维数组ans里面,然后对每一条路径进行遍历 ,如果所有路径都是递增的,说明是Min Heap,如果所有的路径都是递减的,说明是Max Heap,否则就是Not Heap。然后对树进行后序遍历,输出
上AC代码:
#include <iostream>
#include<bits/stdc++.h>
using namespace std;
int m,n,heap[1001];
vector< vector<int> > ans;
void dfs(int index,vector<int> v)
{
if(index>n)
return;
v.push_back(heap[index]);
if(2*index>n)
{
ans.push_back(v);
}
dfs(2*index,v);
dfs(2*index+1,v);
v.pop_back();
}
int judge(vector<int> v)
{
int sum=0;
for(int i=1;i<v.size();i++)
if(v[i] >v[i-1])
sum++;
if(sum==v.size()-1)
return 1;///大
sum=0;
for(int i=1;i<v.size();i++)
if(v[i] <v[i-1])
sum++;
if(sum==v.size()-1)
return -1;///xiao
return 0;///not
}
void post(int index,vector<int> &ans)
{
if(index>n)
return ;
post(2*index,ans);
post(2*index+1,ans);
ans.push_back(heap[index]);
}
int main()
{
cin>>m>>n;
for(int i=1;i<=m;i++)
{
ans.clear();
for(int j=1;j<=n;j++)
cin>>heap[j];
vector<int> v;
dfs(1,v);
int num1=0,numfu=0;
for(int j=0;j<ans.size();j++)
{
if(judge(ans[j])==1)
num1++;
else if(judge(ans[j])==-1)
numfu++;
}
if(num1==ans.size())
cout<<"Min Heap"<<endl;
else if(numfu==ans.size())
cout<<"Max Heap"<<endl;
else
cout<<"Not Heap"<<endl;
vector<int> h;
post(1,h);
for(int j=0;j<h.size();j++)
{
cout<<h[j];
if(j==h.size()-1)
cout<<endl;
else
cout<<" ";
}
}
return 0;
}