暴力枚举。代码能力有待提高,比赛的时候老是敲错,多敲题。我要! 加油!!!Lin!!!
/*
Pro: 0
Sol:
date:
*/
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstring>
#include <cmath>
#include <queue>
#include <set>
#include <map>
#include <vector>
using namespace std;
int t,n;
string people[10];
map <string , int> mp;
int a[10],b[10];
bool grid[10][10];
int main(){
scanf("%d",&t);
for(int ca = 1; ca <= t; ca ++){
scanf("%d",&n);
mp.clear();
memset(grid,false,sizeof(grid));
for(int i = 1; i <= n;i ++)
cin >> people[i];
sort(people + 1, people + 1 + n);
for(int i = 1; i <= n; i ++)
mp[people[i]] = i;
for(int i = 1; i <= n; i ++){
int k; char name[20];
scanf("%d",&k);
while(k --){
scanf("%s",name);
grid[i][mp[name]] = true;// a can defeat b
}
}
for(int i = 1; i <= n; i ++) a[i] = i;
bool flag ;
do{
//for every a sequence
for(int j = 1; j <= n; j ++)
b[j] = j;
flag = true;
do{
int pa = 1; int pb = 1;
while(pa <= n && pb <= n){
if(grid[b[pb]][a[pa]]) // b can defeat a
pa ++;
else
pb ++;
}
if(pa > n) flag = false;// i lose once, then this sequence is not the answer
}while(next_permutation(b + 1, b + 1 + n));
if(flag) break;//represents that a all wins
}while(next_permutation(a + 1, a + 1 + n));
// for(int i = n; i > 1; i --)
// printf("%d ",a[i]); printf("%d\n",a[1]);
printf("Case %d: ",ca);
if(flag) {
printf("Yes\n");
for(int i = 1; i < n; i++)
printf("%s ",people[a[i]].c_str()); printf("%s\n",people[a[n]].c_str());
}else
printf("No\n");
}
return 0;
}