给你一个整数 n
,找出从 1
到 n
各个整数的 Fizz Buzz 表示,并用字符串数组 answer
(下标从 1 开始)返回结果,其中:
answer[i] == "FizzBuzz" 如果 i 同时是 3 和 5 的倍数。
answer[i] == "Fizz" 如果 i 是 3 的倍数。
answer[i] == "Buzz" 如果 i 是 5 的倍数。
answer[i] == i (以字符串形式)如果上述条件全不满足。
示例 1:
输入:n = 3
输出:["1","2","Fizz"]
示例 2:
输入:n = 5
输出:["1","2","Fizz","4","Buzz"]
示例 3:
输入:n = 15
输出:["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]
提示:
1 <= n <= 104
代码:
class Solution {
public List<String> fizzBuzz(int n) {
List<String> answer=new ArrayList<String>();
for(int i =1;i<=n;i++){
if(i%15==0){
answer.add("FizzBuzz");
}
else if(i%3==0){
answer.add("Fizz");
}
else if(i%5==0){
answer.add("Buzz");
}
else{
answer.add(Integer.toString(i));
}
}
return answer;
}
}