php openssl_private_decrypt,openssl_private_decrypt（）与cryptico.js密文返回false

$res = openssl_pkey_new(array(

'private_key_bits' => 2048,

'private_key_type' => OPENSSL_KEYTYPE_RSA,

'digest_alg' => 'sha256'

));

//Made Public key compatible with cryptico.js

$detail = openssl_pkey_get_details($res);

$n = base64_encode($detail['rsa']['n']);

$e = bin2hex($detail['rsa']['e']);

$publicKey = "$n|$e";

openssl_pkey_export($res, $privateKey);

file_put_contents("public_key",$publicKey);

file_put_contents("private_key",$privateKey);

制造cryptico.js两处修改为在同一职位建议

my.publicKeyFromString = function(string)

{

var tokens = string.split("|");

var N = my.b64to16(tokens[0]);

var E = tokens.length > 1 ? tokens[1] : "03";

var rsa = new RSAKey();

rsa.setPublic(N, E);

return rsa

}

my.encrypt = function(plaintext, publickeystring, signingkey)

{

var cipherblock = "";

try

{

var publickey = my.publicKeyFromString(publickeystring);

cipherblock += my.b16to64(publickey.encrypt(plaintext));

}

catch(err)

{

return {status: "Invalid public key"};

}

return {status: "success", cipher: cipherblock};

}

现在，在客户端JS：

var publicKey = '';

var encrypted = cryptico.encrypt("plain text", publicKey);

var data = 'encrypted_post_var='+encrypted.chiper;

然后我通过AJAX POST发送数据，我可以证实，它已与$ _ POST [ “encrypted_post_var”]

被成功接收在PHP中：

$private = openssl_pkey_get_private(file_get_contents("private_key"));

//!!! THAT is the problem because here openssl_private_decrypt() return FALSE !!!

openssl_private_decrypt(base64_decode($_POST["encrypted_post_var"]), $decrypted, $privateKey);

2017-04-15

MTK