very easy 的ajax使用方式
楚浩然
2023-12-01
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Insert title here</title>
<script type="text/javascript" src="js/jquery-1.9.1.js"></script>
<script type="text/javascript">
function fun1(){
$.ajax({
type:"get",//请求方式
url:"AjaxServlet",
data:{uname:"zhangshan",pwd:123},//传递的参数
async:true,//是否异步
cache:false,//是否缓存
success:function(result){
alert(result);
},
error:function(result){
alert("出错");
}
});
}
function fun2get()
{
$.get("AjaxServlet",{uname:"get",pwd:"123"},function(result){
alert(result);
});
}
function fun3post(){
$.post("AjaxServlet",{uname:"post",pwd:"123"},function(result){
alert(result);
});
}
</script>
</head>
<body>
<input type="button" value="testAjex" οnclick="fun1()">
<input type="button" value="get" οnclick="fun2get()">
<input type="button" value="post" οnclick="fun3post()">
</body>
</html>