寻找一些让我入门的建议.
在我的左手中,我有一个运行ICS的SGS2.我已经启动并运行了SL4A并安装了Python 2.6.2
在我的右手中,我有一个通用的中国蓝牙RFID阅读器.它工作,它读取标签(它有一个显示器),它与手机配对.
我希望他们玩得很好 – 我想编写一些能够继续观看设备并在传输时捕获代码的脚本.
我不是Python专家,但我已经使用它一段时间在Web服务器上构建简单的I / O作业,所以我可以找到自己的方法.
不同寻常的是,我遇到了实际问题 – 我找不到任何“开始使用蓝牙和SL4A”资源来克服建立持久连接和监控输出的第一步.
有小费吗?
解决方法:
看来你需要的是蓝牙外观.以下是一些与蓝牙相关的命令,可能对您有所帮助:
bluetoothAccept
bluetoothActiveConnections
bluetoothConnect
bluetoothDiscoveryCancel
bluetoothDiscoveryStart
bluetoothGetConnectedDeviceName
bluetoothGetLocalAddress
bluetoothGetLocalName
bluetoothGetRemoteDeviceName
bluetoothGetScanMode
bluetoothIsDiscovering
bluetoothMakeDiscoverable
bluetoothRead
bluetoothReadBinary
bluetoothReadLine
bluetoothReadReady
bluetoothSetLocalName
bluetoothStop
bluetoothWrite
bluetoothWriteBinary
checkBluetoothState
toggleBluetoothState
要调用这些命令中的任何一个,你会做类似的事情
import android
droid = android.Android()
#call your commands with droid.bluetoothcommand
droid.bluetoothDiscoveryStart()
#or
droid.toggleBluetoothState(True)
以下是一些蓝牙功能的示例,它包含在SL4A中,但为了清晰起见,我添加了注释:
import android #for bluetooth functions
import time #for waiting
#get everything setup
droid = android.Android()
#turn on bluetooth
droid.toggleBluetoothState(True)
#ask user
droid.dialogCreateAlert('Be a server?')
droid.dialogSetPositiveButtonText('Yes')
droid.dialogSetNegativeButtonText('No')
droid.dialogShow()
#get user response to question
result = droid.dialogGetResponse()
#if the result is 'Yes' ('positive') then is_server is set to True
is_server = result.result['which'] == 'positive'
if is_server:
#so if is_server is true make the device discoverable and accept the next connection
droid.bluetoothMakeDiscoverable()
droid.bluetoothAccept()
else:
#attempts to connect to a device over bluetooth, the logic being that if the phone
#is not receiving a connection then the user is attempting to connect to something
droid.bluetoothConnect()
if is_server:
result = droid.getInput('Chat', 'Enter a message').result #Gets a message to send
#via bluetooth
if result is None:
droid.exit() #exit if nothing is in the message
droid.bluetoothWrite(result + '\n') #otherwise write the message
while True: #receives a message
message = droid.bluetoothReadLine().result
droid.dialogCreateAlert('Chat Received', message)
droid.dialogSetPositiveButtonText('Ok')
droid.dialogShow()
droid.dialogGetResponse()
result = droid.getInput('Chat', 'Enter a message').result
if result is None:
break
droid.bluetoothWrite(result + '\n')
droid.exit()
标签:android,python,bluetooth,sl4a
来源: https://codeday.me/bug/20190725/1537943.html