原题
Given an array of citations (each citation is a non-negative integer) of a researcher,
write a function to compute the researcher's h-index.
According to the definition of h-index on Wikipedia:
"A scientist has index h if h of his/her N papers
have at least h citations each, and the other N − h
papers have no more than h citations each."
For example, given citations = [3, 0, 6, 1, 5],
which means the researcher has 5 papers in total
and each of them had received 3, 0, 6, 1, 5 citations respectively.
Since the researcher has 3 papers with at least 3 citations each
and the remaining two with no more than 3 citations each, his h-index is 3.
Note: If there are several possible values for h,
the maximum one is taken as the h-index.
思路
直接按wiki上的说来弄.
code
class Solution {
public:
int hIndex(vector<int>& citations) {
sort(citations.begin(), citations.end(), greater<int>());
int i;
for(i = 0; i < citations.size(); i++) {
if(citations[i] <= i) return i;
}
return i;
}
};
原题
Follow up for H-Index:
What if the citations array is sorted in ascending order?
Could you optimize your algorithm?
思路
类似二分查找.
code
class Solution {
public:
int hIndex(vector<int>& citations) {
int len = citations.size();
int l = 0, r = len - 1;
while(l <= r) {
int m = l + ((r - l) >> 1);
int m2 = len - m;
if(m2 <= citations[m]) {
r = m - 1;
} else {
l = m + 1;
}
}
return len - l;
}
};