python编辑环境 ios_Python/Kivy环境在IOS上写入iCloud文档的数据-问答-阿里云开发者社区-阿里云...

使用Python/Kivy为iOS/iPhone环境。

应用程序本身运行良好，Python/Kivy->toolchain.py->XCode->iPhone操作。

我希望通过iCloud为多个平台共享应用程序数据，因此希望将数据写入iCloud文档存储。我可以做好使用iCloud的所有准备(绑定标识符、AppID、供应配置文件，并成功地激活了XCode上的iCloud和iCloud文档)。然后，我在互联网上没有找到示例代码，也没有找到如何使用Python/Kivy将数据写入iCloud文档存储或将数据从存储复制到iCloud文档存储的书籍。也许，如果我可以使用Python/Kivy使函数等价于以下SWIFT代码，我就能够解决这个问题。

let manager = NSFileManager()

let manager.copyItemAtPath(srcPath, toPath: toPath, error: nil)

有没有办法使用Python/Kivy将数据写入iCloud或将数据从用户存储复制到iCloud存储？下面是一个示例代码，我想添加这样的函数。

from kivy.app import App

import os

import pickle

setting_in = {'parameter1': 'abcde', 'parameter2': 'fghij'}

setting_out = {}

def readsetting(read_settingfilename):

setting1 = {}

if os.path.exists(read_settingfilename):

try:

with open(read_settingfilename, 'rb') as f1:

try:

setting1 = pickle.load(f1)

except pickle.UnpicklingError:

print('Read error!')

else:

print('********** File' + read_settingfilename + 'was read!! **********')

except IOError:

print('File' + read_settingfilename + 'could not be opened for reading')

else:

pass

return setting1

def writesetting(write_settingfilename, setting1):

try:

with open(write_settingfilename, 'wb') as f:

try:

pickle.dump(setting1,f)

except pickle.PicklingError:

print('File output error!')

outputflag = 1

else:

print('********** File created!! **********')

outputflag = 0

except IOError:

print('File' + write_settingfilename + 'could not be opened for writing')

outputflag = 1

return outputflag

DATAPATH = App().user_data_dir + 'test/'

if os.path.isdir(DATAPATH) == False:

os.mkdir(DATAPATH)

datafilename = 'test.dat'

writesetting(DATAPATH + datafilename, setting_in)

setting_out = readsetting(DATAPATH + datafilename)

print(setting_out)