我想用这样的离散值求解非线性多变量方程:
x*y + z + t - 10 = 0
有约束:
10 < x < 100
等等..
我正在尝试使用Choco库来做,但是我有点迷茫.
我发现此代码:
// 1. Create a Solver
Solver solver = new Solver("my first problem");
// 2. Create variables through the variable factory
IntVar x = VariableFactory.bounded("X", 0, 5, solver);
IntVar y = VariableFactory.bounded("Y", 0, 5, solver);
// 3. Create and post constraints by using constraint factories
solver.post(IntConstraintFactory.arithm(x, "+", y, "
// 4. Define the search strategy
solver.set(IntStrategyFactory.lexico_LB(x, y));
// 5. Launch the resolution process
solver.findSolution();
//6. Print search statistics
Chatterbox.printStatistics(solver);
但我不明白我将方程式放在哪里.
解决方法:
是的,更准确地说,您应该将方程分解为几个约束:
10 < x < 100
变成
solver.post(ICF.arithm(x,">",10));
solver.post(ICF.arithm(x,"
和
x*y + z + t - 10 = 0
变成
// x*y = a
IntVar a = VF.bounded("x*y",-25,25,solver);
solver.post(ICF.times(x,y,a);
// a+z+t=10
IntVar cst = VF.fixed(10,solver);
solver.post(ICF.sum(new IntVar[]{a,z,t},cst));
最好,
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标签:equation-solving,java,choco
来源: https://codeday.me/bug/20191119/2034220.html