rapidjson将嵌套map转为嵌套json------人生苦短,我用rapidjson
看代码:
#include <iostream> #include <map> // 请自己下载开源的rapidjson #include "rapidjson/prettywriter.h" #include "rapidjson/rapidjson.h" #include "rapidjson/document.h" #include "rapidjson/stringbuffer.h" #include "rapidjson/writer.h" #include "rapidjson/memorystream.h" using namespace std; using rapidjson::Document; using rapidjson::StringBuffer; using rapidjson::Writer; using namespace rapidjson; string formJson(const map<string, int> &mInt, const map<string, string> &mString, const string &strChild, const map<string, int> &mChildInt, const map<string, string> &mChildString) { Document document; Document::AllocatorType& allocator = document.GetAllocator(); Value root(kObjectType); Value child(kObjectType); Value key(kStringType); Value value(kStringType); // 当前级别 for(map<string, int>::const_iterator it = mInt.begin(); it != mInt.end(); ++it) { key.SetString(it->first.c_str(), allocator); root.AddMember(key, it->second, allocator); } for(map<string, string>::const_iterator it = mString.begin(); it != mString.end(); ++it) { key.SetString(it->first.c_str(), allocator); value.SetString(it->second.c_str(), allocator); root.AddMember(key, value, allocator); } // 孩子级别 if(!strChild.empty()) { for(map<string, int>::const_iterator it = mChildInt.begin(); it != mChildInt.end(); ++it) { key.SetString(it->first.c_str(), allocator); child.AddMember(key, it->second, allocator); } for(map<string, string>::const_iterator it = mChildString.begin(); it != mChildString.end(); ++it) { key.SetString(it->first.c_str(), allocator); value.SetString(it->second.c_str(), allocator); child.AddMember(key, value, allocator); } key.SetString(strChild.c_str(), allocator); root.AddMember(key, child, allocator); } StringBuffer buffer; Writer<StringBuffer> writer(buffer); root.Accept(writer); return buffer.GetString(); } int main(int argc, char *argv[]) { map<string, int> mInt; mInt["code"] = 0; mInt["score"] = 80; map<string, string> mString; mString["name"] = "taoge"; mString["place"] = "shenzhen"; string strChild = "childNode"; map<string, int> mChildInt; mChildInt["code"] = 0; mChildInt["score"] = 100; map<string, string> mChildString; mChildString["name"] = "taogeChild"; mChildString["place"] = "shenzhen"; string strJson = formJson(mInt, mString, strChild, mChildInt, mChildString); cout << strJson << endl; return 0; }
结果:
{"code":0,"score":80,"name":"taoge","place":"shenzhen","childNode":{"code":0,"score":100,"name":"taogeChild","place":"shenzhen"}}
另外, 如果仅仅想有当前界别, 那么, 可以这么搞(C++默认参数搞起):
#include <iostream> #include <map> // 请自己下载开源的rapidjson #include "rapidjson/prettywriter.h" #include "rapidjson/rapidjson.h" #include "rapidjson/document.h" #include "rapidjson/stringbuffer.h" #include "rapidjson/writer.h" #include "rapidjson/memorystream.h" using namespace std; using rapidjson::Document; using rapidjson::StringBuffer; using rapidjson::Writer; using namespace rapidjson; map<string, int> g_mChildInt; map<string, string> g_mChildString; string formJson(const map<string, int> &mInt, const map<string, string> &mString, const string &strChild="", const map<string, int> &mChildInt=g_mChildInt, const map<string, string> &mChildString=g_mChildString) { Document document; Document::AllocatorType& allocator = document.GetAllocator(); Value root(kObjectType); Value child(kObjectType); Value key(kStringType); Value value(kStringType); // 当前级别 for(map<string, int>::const_iterator it = mInt.begin(); it != mInt.end(); ++it) { key.SetString(it->first.c_str(), allocator); root.AddMember(key, it->second, allocator); } for(map<string, string>::const_iterator it = mString.begin(); it != mString.end(); ++it) { key.SetString(it->first.c_str(), allocator); value.SetString(it->second.c_str(), allocator); root.AddMember(key, value, allocator); } // 孩子级别 if(!strChild.empty()) { for(map<string, int>::const_iterator it = mChildInt.begin(); it != mChildInt.end(); ++it) { key.SetString(it->first.c_str(), allocator); child.AddMember(key, it->second, allocator); } for(map<string, string>::const_iterator it = mChildString.begin(); it != mChildString.end(); ++it) { key.SetString(it->first.c_str(), allocator); value.SetString(it->second.c_str(), allocator); child.AddMember(key, value, allocator); } key.SetString(strChild.c_str(), allocator); root.AddMember(key, child, allocator); } StringBuffer buffer; Writer<StringBuffer> writer(buffer); root.Accept(writer); return buffer.GetString(); } int main(int argc, char *argv[]) { map<string, int> mInt; mInt["code"] = 0; mInt["score"] = 80; map<string, string> mString; mString["name"] = "taoge"; mString["place"] = "shenzhen"; string strJson = formJson(mInt, mString); cout << strJson << endl; return 0; }
结果:
{"code":0,"score":80,"name":"taoge","place":"shenzhen"}
其实, 上面的formJson函数, 还可以继续扩展。
总结
以上就是这篇文章的全部内容了,希望本文的内容对大家的学习或者工作具有一定的参考学习价值,谢谢大家对小牛知识库的支持。如果你想了解更多相关内容请查看下面相关链接
本文向大家介绍C++中rapidjson将map转为json的方法,包括了C++中rapidjson将map转为json的方法的使用技巧和注意事项,需要的朋友参考一下 rapidjson将map转为json------人生苦短,我用rapidjson 直接撸代码: 结果: {"name":"taoge","place":"shenzhen"} 来,继续改: 结果: {"age":29,"score
问题内容: 我是Python和Pandas的新手。我正在尝试将Pandas Dataframe转换为嵌套的JSON。函数.to_json()不能为我的目标提供足够的灵活性。 以下是数据框的一些数据点(在csv中,以逗号分隔): 有很多重复的信息,我想要一个这样的JSON: 我怎样才能做到这一点? 编辑: 再现数据帧的代码: 问题答案: 更新: 结果(格式化): 旧答案: 你可以用它做的,和方法:
我遇到了一个问题,我的程序只在的一次迭代中结束,我不确定不合逻辑的代码在哪里。 全球给予: 我复杂的嵌套从这里开始,但我不确定如何修复它,以便它迭代通过和数字for-循环: 我得到以下输出: 我从来没有得到Susie的数据,我很早就回来了,但似乎不知道在哪里。对于问题所在(甚至重构)的任何帮助/指导都将不胜感激。提前谢谢!
我有两个嵌套的case类: 当然,解决方案应该是泛型的,并且适用于任何case类。 注意:这个讨论很好地回答了如何将单个case类映射到映射。但我无法将其用于嵌套的case类。相反,我得到了:
如何使用jolt转换将平面JSON转换为嵌套JSON?我对JSON和jolt是新手。 输入: 预期输出: 编辑:我想在< code>SubFunds中添加一个新字段,但是新字段不在JSON文件中,它是计算字段,我可以按原样添加示例吗 并重命名字段:
我有一个JSON如下所示: 为什么在输出中看不到Level1、Level2?请有人帮忙,我想看看在输出和输入太相似了。