无法使您的两个或多个方法在同一路由中

Question

到项目的链接https://github.com/kammikazy/project i can't make work my get two or more methods in same route我有代码404 i使用mysql nodejs和express my code
控制器联盟

const User = require('../models/Alliances')

const findAlianca = async (connection,  req, res) => {

  const Allianca = await User.find(connection, req.session.user.username)
  if (!Allianca) {
 res.status(404).send('Nenhuma cidade encontrada.');
 return;
}
console.log("dddd");
          req.session.Allianca = Allianca
          res.locals.Allianca = Allianca
res.render('Administration/Alliances')
  }

  module.exports = {
   findAlianca
  }

路由异形

const express = require('express')
const router = express.Router()
const connection = require('../../Config/database')
const controllerAdmin = require('../../controllers/Administration')
const controlleruser = require('../../controllers/Alliances')
router.get('/Administration/Alliances', (req, res) => controllerAdmin.findcidade3(connection, req, res))
router.get('/Administration/Alliances/limitado', (req, res) => controlleruser.findAlianca(connection, req, res))


module.exports = app => app.use('/', router)

模型异形

常量find=（连接，用户名）=>；{返回新承诺（（resolve，reject）=>{connection.query(select alianca.nome，alianca.n_membros，alianca.tag FROM user INNER JOIN alianca ON user.cod_alianca=alianca.id WHERE user.username='${username}'，（err，result)=>{if（err）{reject（err）}else{resolve（result）}}）}）}

    module.exports = {
        find
    }

青玉联盟

extends layout
block title
   .col-xs-6.col-xs-offset-3.col-sm-6.col-sm-offset-3
   .col-sm-4(style='width:76%')
    div.panel.panel-primary(style='height:50px') Alliances Page
    div.panel.panel-primary(style='height:700px')  fdssdklfsdklfjskldfjkldsjfl
      if locals.user.cod_alianca==null
         p You Dont Have Alliances
      else 
         br
         span Your Aliance
         span= locals.Allianca.nome
   .col-xs-2.panel-red(style='width:24%;height:100%;text-align:center')

我的应用程序

require('./routes/Administration/Alliances')(app)

我的连接数据库

const mysql = require('mysql')
const config = require( "./config.json" )
const connection =mysql.createConnection({
 host:config.host,
 user:config.user,
 password:config.password,
 database:config.database,
// port:config.port
});

connection.connect((err) =>{
    if(err){
        console.log(err)
        process.exit(0)
    }else{
    console.log('database on')
}
})

我做错了什么我找不到解决问题的办法

Answer 1

我问题的解决方法

const express = require('express')
    const router = express.Router()
    const connection = require('../../Config/database')
    const controllerAdmin = require('../../controllers/Administration')
    const controlleruser = require('../../controllers/Alliances')

    router.get('/Administration/Alliances', (req, res, next) => {
        //Do something here and to add data to your request use
      controllerAdmin.findcidade3(connection, req, res)
        next();
    }, (req, res, next) => {
        //Can continue this cycle of calling next function until last `sendResponse` function is reached.
        //Can even set `error` in request for `sendResponse`
      controlleruser.findAlianca(connection, req, res)
    })
   module.exports = app => app.use('/', router)

Answer 2

不确定您在询问什么，但是，如果您想在同一个路由/API中调用多个函数，可以执行以下操作:

使用ExpressJ，您可以使用next函数，如:

app.get('/Administration/Alliances', (req, res, next) => { 
    //Do something here and to add data to your request use
    req.body.newData = 'newData';
    //after this just call next function
    next();
}, (req, res, next) => {
    //Can continue this cycle of calling next function until last `sendResponse` function is reached.
    //Can even set `error` in request for `sendResponse` 
    req.error = "Some error";
    next();
}, (req, res) => {
    if(req.error) {
        res.status(400).send(req.error);
    } else {
        res.status(200).send(req.body.result);
    }
});