如何使用Python执行cURL命令？

Question

curl -d @request.json --header "Content-Type: application/json" https://www.googleapis.com/qpxExpress/v1/trips/search?key=mykeyhere

import pycurl
import StringIO

response = StringIO.StringIO()
c = pycurl.Curl()
c.setopt(c.URL, 'https://www.googleapis.com/qpxExpress/v1/trips/search?key=mykeyhere')
c.setopt(c.WRITEFUNCTION, response.write)
c.setopt(c.HTTPHEADER, ['Content-Type: application/json','Accept-Charset: UTF-8'])
c.setopt(c.POSTFIELDS, '@request.json')
c.perform()
c.close()
print response.getvalue()
response.close()

错误消息是parse error。如何正确地从服务器获得响应？

Answer 1

为了简单起见，也许您应该考虑使用请求库。

一个包含json响应内容的示例如下：

import requests
r = requests.get('https://github.com/timeline.json')
r.json()

如果您想了解更多的信息，在快速入门部分，他们有很多工作示例。

import requests
url = 'https://www.googleapis.com/qpxExpress/v1/trips/search?key=mykeyhere'
payload = open("request.json")
headers = {'content-type': 'application/json', 'Accept-Charset': 'UTF-8'}
r = requests.post(url, data=payload, headers=headers)