如何记录spring-webflux WebClient请求+响应的详细信息（主体、头、elasped_time)？

Question

基本上，我希望用SpringWebClient将请求/响应信息记录在一个包含正文/标题的日志中。

使用SpringRestTemplate，我们可以使用ClientHTTPrequestInterceptor来实现这一功能。我找到了关于ExchangeFilterFunctionfor SpringWebClient，但还没有以一种干净的方式做类似的事情。我们可以使用这个过滤器并记录请求和响应，但我需要在相同的日志跟踪两者。

{
    "@timestamp": "2019-05-14T07:11:29.089+00:00",
    "@version": "1",
    "message": "GET https://awebservice.com/api",
    "logger_name": "com.sample.config.resttemplate.LoggingRequestInterceptor",
    "thread_name": "http-nio-8080-exec-5",
    "level": "TRACE",
    "level_value": 5000,
    "traceId": "e65634ee6a7c92a7",
    "spanId": "7a4d2282dbaf7cd5",
    "spanExportable": "false",
    "X-Span-Export": "false",
    "X-B3-SpanId": "7a4d2282dbaf7cd5",
    "X-B3-ParentSpanId": "e65634ee6a7c92a7",
    "X-B3-TraceId": "e65634ee6a7c92a7",
    "parentId": "e65634ee6a7c92a7",
    "method": "GET",
    "uri": "https://awebservice.com/api",
    "body": "[Empty]",
    "elapsed_time": 959,
    "status_code": 200,
    "status_text": "OK",
    "content_type": "text/html",
    "response_body": "{"message": "Hello World!"}"
}

有人能用Spring WebClient做这样的事情吗？或者，如何使用Spring WebClient跟踪请求/请求问题？

Answer 1

您可以使用filter()，如下所示：

this.webClient = WebClient.builder().baseUrl("your_url")
            .filter(logRequest())
            .filter(logResponse())
            .build();

private ExchangeFilterFunction logRequest() {
    return (clientRequest, next) -> {
        log.info("Request: {} {}", clientRequest.method(), clientRequest.url());
        clientRequest.headers()
                .forEach((name, values) -> values.forEach(value -> log.info("{}={}", name, value)));
        return next.exchange(clientRequest);
    };
}

private ExchangeFilterFunction logResponse() {
    return ExchangeFilterFunction.ofResponseProcessor(clientResponse -> {
        log.info("Response: {}", clientResponse.headers().asHttpHeaders().get("property-header"));
        return Mono.just(clientResponse);
    });
}