javascript - sku,通过已有的sku组合和用户选中的sku，输出全部的规格？

Question

商品的sku组合:

[    ['白','X','中年'],    ['白','X','老年'],    ['白','XL','老年'],    ['黑','X','中年'],    ['黑','X','老年'],    ['黑','XL','中年'],    ['黑','XL','老年']]

用户选择的规格: ["白","XL",""]

通过两组数据得知，当用户选中的规格是["白","XL",""]时在sku组合中并没有["白","XL","中年"]组合，所以中年是禁止选中的。规格的数量和名称不是固定的

怎么用js开发一个函数，输出的是全部规格的可选状态

[    {        "白":true,        "黑":true    },    {        "X":true,        "XL":true    },    {        "中年":false,        "老年":true    }]

Answer 1

function getSpecStatus(skuCombinations, userSelection) {  const specStatus = Array.from({ length: userSelection.length }, () => ({}));  skuCombinations.forEach(sku => {    sku.forEach((spec, index) => {      if (userSelection[index] === "" || userSelection[index] === spec) {        specStatus[index][spec] = specStatus[index][spec] || false;      }    });  });  skuCombinations.forEach(sku => {    let match = true;    for (let i = 0; i < sku.length; i++) {      if (userSelection[i] !== "" && userSelection[i] !== sku[i]) {        match = false;        break;      }    }    if (match) {      for (let i = 0; i < sku.length; i++) {        specStatus[i][sku[i]] = true;      }    }  });  return specStatus;}const skuCombinations = [  ['白', 'X', '中年'],  ['白', 'X', '老年'],  ['白', 'XL', '老年'],  ['黑', 'X', '中年'],  ['黑', 'X', '老年'],  ['黑', 'XL', '中年'],  ['黑', 'XL', '老年']];const userSelection = ["白", "XL", ""];console.log(getSpecStatus(skuCombinations, userSelection));