nginx"对脚本'xxx/xxx/php'的访问被拒绝（见security.limit_extensions）"

Question

我得到了这个错误。显然，我想使用ckfinder文件上传。

Access to the script '/var/www/example.com/public/admin/scripts/vendor/ckfinder
/core/connector/php' has been denied (see security.limit_extensions) while reading 
response header from upstream, client: x.x.x.x, server: 
example.com, request: "GET /admin/scripts/vendor/ckfinder/core/
connector/php/connector.php HTTP/1.1", upstream: "fastcgi://127.0.0.1:9000", 
host: "example.com"

我已经设置了security.limit_extensions到. php。我已经看了访问拒绝（403）的PHP文件与Nginx PHP-FPM和我尝试了大部分（除了fix_pathinfo）没有运气。在我注意到错误消息中的脚本路径之前，来自connector.php的GET请求位于php/目录中。我认为问题是nginx看到这个目录名作为脚本，并试图运行它，不确定。

这是我的nginx服务器块。

server {
    listen 80;

    root /var/www/example.com/public;
    index index.html index.htm index.php app.php app_dev.php;

    # Make site accessible from ...
    server_name example.com;

    access_log /var/log/nginx/example.com-access.log;
    error_log  /var/log/nginx/example.com-error.log error;

    charset utf-8;

    location / {
        # try_files \$uri \$uri/ /app.php?\$query_string /index.php?\$query_string;
        try_files $uri $uri/ /index.php?\$query_string;
    }

    location = /favicon.ico { log_not_found off; access_log off; }
    location = /robots.txt  { access_log off; log_not_found off; }

    error_page 404 /index.php;

    location = /admin/scripts/vendor/ckfinder/core/connector/php/connector.php {
        try_files $uri =404;
        fastcgi_split_path_info ^(.+.php)(/.+)$;
        # With php5-fpm:
        fastcgi_pass 127.0.0.1:9000;
        fastcgi_index index.php;
        include fastcgi_params;
        fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name;
        fastcgi_param LARA_ENV local; # Environment variable for Laravel
        fastcgi_param HTTPS off;
    }
    location ~ \.php$ {
        try_files $uri =404;
        fastcgi_split_path_info ^(.+.php)(/.+)$;
        # With php5-fpm:
        fastcgi_pass 127.0.0.1:9000;
        fastcgi_index index.php;
        include fastcgi_params;
        fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name;
        fastcgi_param LARA_ENV local; # Environment variable for Laravel
        fastcgi_param HTTPS off;
    }

    # Deny .htaccess file access
    location ~ /\.ht {
        deny all;
    }
}

我的问题是如何指示nginx知道php/是一个路径，而不是一个脚本？

Answer 1

fastcgi\u split\u path\u info指令中有错误。正则表达式。php将匹配以下字符串：至少1个字符，然后是任意字符，然后是文本“php”。

您需要转义点（\.），因此它并不表示任何字符，只表示点本身。

因此，正确的语法应该是：

  fastcgi_split_path_info ^(.+\.php)(/.+)$;