在异步中尝试捕获的问题等待

Question

我正在与async Wait try catch块斗争几天。

async function executeJob(job) {

  // necessary variable declaration code here

  try {
    do {
      let procedureRequests = await ProcedureRequestModel.find(filter, options);

      // doing process here...

    } while (fetchedCount < totalCount);

    providerNPIIds = [...providerNPIIds];

    // Fetch provider details
    let providerDetails = await esHelper.getProvidersById(providerNPIIds, true);

    try {

      let updateProviderCount = await UserProvider.updateAll(
          {
            userId: userId
          },
          {
            providers: providerNPIIds,
            countByType: providerCountType
          });

      if(updateProviderCount) {
        try {
          let destroyJobId = await  app.models.Job.destroyById(job.idd);
        } catch (e) {
          var err = new QueueError();
          console.log(err instanceof QueueError);
          throw new QueueError();
        }

      }
    } catch (e) {
      logger.error('Failed to update UserProviders  & Count: %O', err);
      throw e;
    }

    executeNextJob();
  } catch (e) {
    if(e instanceof QueueError) {
      console.log('Exiting from process');
      process.exit(1);
    } else {
      console.log('Working Code');
      buryFailedJobAndExecuteNext(job);
    }

  }
}

这个异步函数中的try-catch是否正确？

这就是我创建自定义错误类并全局导出的方式。

// error.js file

class QueueError extends Error {

}

global.QueueError = QueueError;

要求：

故意换了工作。我想找份工作。国际直拨电话

let destroyJobId = await  app.models.Job.destroyById(job.idd); 

这样我就能抓住错误。如果有错误，则抛出新创建的自定义错误类。但抛出队列错误将导致日志记录

logger.error('Failed to update UserProviders  & Count: %O', err); 

同样，即使不需要捕捉那个里的错误，因为try块在工作，若我抛出QueueError，我只想捕捉最后一个catch块中的错误。

下面是回调版本，我将其转换为异步等待。

 Updating providersNPIId & category count
     UserProvider.updateAll({userId: userId},
       {
         providers: providerNPIIds,
         countByType: providerCountType,
       }, function(err, data) {
         if (err) {
           logger.error('Failed to update UserProviders  & Count: %O', err);
           // throw new QueueError();
         }
         // Remove countProvider Job
         app.models.Job.destroyById(job.id, function(err) {
           if (err) {
             logger.error('Failed to remove countProvider job: %O', err);

           }
         });
       });

Answer 1

这与您拥有的基本相同：

1 function myFunctionPromise() {                                                                                     
2   return new Promise((response, reject) => {                                                                       
3       setTimeout(() => reject("Reject Err"), 3000);                                                                
4   });                                                                                                              
5 } 

7 async function myFunction() {                                                                                      
8      try {                                                                                                         
9        try {                                                                                                       
10          await myFunctionPromise();                                                                                
11        } catch(e) {                                                                                                
12          console.log("Second Err");                                                                                
13          throw e;                                                                                                  
14        }
15 
16      } catch (e) {                                                                                                 
17        throw e;
18      }
19 
20      console.log("test");
21 }
22 
23 
24 myFunction()

我看到的唯一区别是拒绝了promise线3。所以我想知道：

app.models.Job.destroyById（job.idd）

这就是拒绝promise。

Answer 2

您可以在较小的函数中重构代码，这些函数返回一个promise，您可以在本地包装try-catch并处理它。

async function executeJob(job) {

  // necessary variable declaration code here
  try {

    await doProcedure();

    providerNPIIds = [...providerNPIIds];

    // Fetch provider details
    let providerDetails = await esHelper.getProvidersById(providerNPIIds, true);
    const updateProviderCount = await getProviderCount(userId, providerNPIIds, providerCountType);

    if(updateProviderCount) {
        await destroyJobById(job.idd);
    }

    executeNextJob();
  } catch (e) {
    if(e instanceof QueueError) {
      console.log('Exiting from process');
      process.exit(1);
    } else {
      console.log('Working Code');
      buryFailedJobAndExecuteNext(job);
    }
  }
}

async function doProcedure() {
    try {
        do {
          let procedureRequests = await ProcedureRequestModel.find(filter, options);

          // doing process here...

        } while (fetchedCount < totalCount);
    } catch (err) {
        throw err;
    }
}

async function getProviderCount(userId, providerNPIIds, providerCountType) {
    try {
        let updateProviderCount = await UserProvider.updateAll({ userId: userId }, { providers: providerNPIIds, countByType: providerCountType });
        return updateProviderCount;
    } catch (err) {
      logger.error('Failed to update UserProviders  & Count: %O', err);
      throw e;
    }
}

async function destroyJobById(Id) {
    try {
          let destroyJobId = await app.models.Job.destroyById(Id);
    } catch (err) {
          throw err;
    }
}