这里是我的代码，我想在数据库中保存图像url我正在使用laravel我的问题是如何在数据库中保存图像url

Question

这里是我的代码，我想在数据库中保存图像url我正在使用laravel我的问题是如何在数据库中保存图像url

公共函数保存（请求$req）{if（请求（）-

        $path = base_path() . '/public/user-uploads/employee-docs/';
        $repath = '/public/user-uploads/employee-docs/'.request('project');


        if (!file_exists($path))
        {
            mkdir($path);
        }
    $path = $path.'/'.request('project');
    if (!file_exists($path))
        {
            mkdir($path);
        }

         $name = Carbon::now()->format('Y-m-d-H-i-s_u');

        $file1 = request()->file('photo');
        if($file1->isValid()) {
            $file1->move($path, $name.'.'.$file1->getClientOriginalExtension());
            $file1_url = $repath.'/'.$name.'.'.$file1->getClientOriginalExtension();
            $photo = new attendance;
        $photo ->user_id=$req->user_id;
        $photo ->image_url=$req->image_url;
            return ['status'=>1, 'data'=>$file1_url];
        } else{
            return ['status'=>0, 'data'=>'Invalid image'];

        }

    } else{
        
        return ['status'=>0, 'data'=>'There is no image'];
        
    }
}   

Answer 1

看起来您尚未保存对象$photo

$photo = new attendance;
$photo->user_id=$req->user_id;
$photo->image_url=$req->image_url;
$photo->save() // add this line