编写一条规则，根据访问情况检测商店某个部门中的客户位置

Question

我刚开始流口水，有一些问题。我正在制定规则，以检测商店各部门的客户。

我的型号如下：

客户：Id，点（x，y）

部门：ID，矩形

客户事件

目前，我用x、y位置或点表示客户，用矩形表示部门。

1）如何编写规则来检测客户是否位于矩形中？

2.）如果客户在一个部门内更改位置至少2次，则触发事件。我如何编写规则来检测客户是否在某个部门，是否已更改位置两次？

请让我知道。

谢啦！

公共类CustomerObj{

public CustomerObj(String custId, Integer timestamp) {
    super();
    this.custId = custId;
    this.timestamp = timestamp;
}
private String custId;
private long timestamp;
private Integer classification;
private Point location;
private Department department;


public long getTimestamp() {
    return timestamp;
}
public void setTimestamp(Integer timestamp) {
    this.timestamp = timestamp;
}
public String getCustId() {
    return custId;
}
public void setCustId(String custId) {
    this.custId = custId;
}
public Integer getClassification() {
    return classification;
}
public void setClassification(Integer classification) {
    this.classification = classification;
}
public Point getLocation() {
    return location;
}
public void setLocation(Point location) {
    this.location = location;
}
public Department getDepartment() {
    return department;
}
public void setDepartment(Department department) {
    this.department = department;
}

}

公共课部{

public Department(Integer departmentId) {
    super();
    this.departmentId = departmentId;
}

private Integer departmentId;
private Rectangle deptLocation;

public Integer getDepartmentId() {
    return departmentId;
}

public void setDepartmentId(Integer departmentId) {
    this.departmentId = departmentId;
}

public boolean containsCustomer(CustomerObj c) {
    if (this.deptLocation.contains(c.getLocation())) return true;
    else return false;
}

}

Answer 1

假设矩形和点来自java。哎呀，事情很简单。

rule "customer in department"
when
    CustomerObj( $cid: custId, $p: point )
    Department( $did: departmentId, $dloc: deptLocation,
                $dloc.contains( $p ) )
then
    System.out.println( "customer " + $cid + " in " + $did );
end

至于移动，您需要一个CustomerEvent，显示客户和部门id以及位置。

rule "customer moves frequently in same department"
when
    CustomerEvent( $cid: custId, $did: dptmtId, $p: Point )
    $dep: Department( departmentId == $did )
    $cust: CustomerObj( custId == $cid, department == $dep, moves >= 1 )
then
    // whatever
end

请注意，您需要其他规则来更改客户中的部门参考和注册第一步，以及可能计算第二步之后的步数。