切换通讯簿错误并跳过输入行

Question

因此，下面的编程作业的寓意是，我需要编写一个地址簿，其中包含第一个、最后一个、地址、城市/州、邮政编码。我必须使用switch语句，但不能使用ioexception或缓冲读取器。LiFiAddressBook文件与LastFirstChapter10分开（但链接在下面的同一框中）。它似乎编译正确，但它在以下错误之间切换：不能在switch语句中使用布尔值，跳过邮政编码输入以选择要搜索的选项，等等。我现在没有确切的错误，因为我正在工作，无法编译以输出确切的错误。只是寻求建议或更正。

“LiFiAddressBook.java类实例变量：名字（字符串）姓氏（字符串）街道地址（字符串）城市状态（字符串）邮政编码（字符串）addEntry方法：获取上面变量的输入。参见底部示例中的示例。搜索方法：接收ArrayList作为参数输出搜索菜单（参见底部示例）使用开关并搜索ArrayList指定的字段。如果找到条目则返回索引号，如果没有找到则返回-1显示方法：打印结果，如底部示例所示。”

LiFiAddressBook.java:33：错误：不兼容的类型开关（isFind1）{^必需：int找到：布尔1错误

import java.util.ArrayList;
import java.util.Scanner;

public class LastFirstChapter10
{

    public static void main(String [] args)
    {

        ArrayList<LiFiAddressBook> aBook = new ArrayList<LiFiAddressBook>();

        String searchStr = null;
        int field = 0;
        Scanner stdIn = new Scanner(System.in);

        int option = 0; ;

        for(int count=0; count<1 ; count++)
        {

                LiFiAddressBook ab = new LiFiAddressBook();
                System.out.println("Please Enter First Name:  ");
                ab.setFirstName(stdIn.next());
                System.out.println("Please Enter Last Name:  ");
                ab.setLastName(stdIn.next());
                System.out.println("Please Enter Street Address:  ");
                ab.setStreetAddress(stdIn.next());
                System.out.println("Please Enter City, State: ");
                ab.setCityState(stdIn.next());
                System.out.println("Please Enter Zip Code:  ");
                ab.setZipCode(stdIn.next());
                aBook.add(ab);

                System.out.println("Enter Search Option:\n"+
                    "1. First Name\n"+
                    "2. Last Name\n"+
                    "3. Street Address\n"+
                    "4. City, State\n"+
                    "5. Zip Code\n");
                option = stdIn.nextInt();
                System.out.println("Enter your search string: ");
                searchStr = stdIn.nextLine();

                int foundIndex = LiFiAddressBook.search(aBook, searchStr, 

field);
                System.out.println();

                if(foundIndex > -1)
                {

                    LiFiAddressBook abc = aBook.get(foundIndex);
                    abc.display();
                }
                else {
                    System.out.println("No entry is found.");

                } // end else

        } //end for

    } //end method

} //end class

  import java.util.ArrayList;

public class LiFiAddressBook {

  private String firstName;
  private String lastName;
  private String streetAddress;
  private String cityState;
  private String zipCode;

  public LiFiAddressBook() {

 }

  public LiFiAddressBook(String firstName,String lastName, String streetAddress,
      String cityState, String zipCode) {
    this.firstName = firstName;
    this.lastName = lastName;
    this.streetAddress = streetAddress;
    this.cityState = cityState;
    this.zipCode = zipCode;

  }

  public static int search(ArrayList<LiFiAddressBook> aBook, String searchStr, int field)

{

    if(aBook != null) {
      boolean isFound = false;
      for(int i=0; i < aBook.size(); i++) {
        LiFiAddressBook ab = aBook.get(i);
        switch(isFound) {
        case 1:
        //if(field == 1)
          isFound = ab.getFirstName().equals(searchStr.trim());
        case 2:
        //if(field == 2)
          isFound = ab.getLastName().equals(searchStr.trim());
        case 3:
        //if(field == 3)
          isFound = ab.getStreetAddress().equals(searchStr.trim());
                case 4:
        //if(field == 4)
          isFound = ab.getCityState().equals(searchStr.trim());
        case 5:
        //if(field == 5)
          isFound = ab.getZipCode().equals(searchStr.trim());
    }
        if(isFound)
          return i;
      }
    }
    return -1;

  }

  public void display() {
    System.out.println("First Name:  "+this.firstName);
    System.out.println("Last Name:  "+this.lastName);
    System.out.println("Street Address:  "+this.streetAddress);
    System.out.println("Zip Code:  "+this.zipCode);
    System.out.println("City, State:  "+this.cityState);
  }

  public String getFirstName() {
    return firstName;
  }

  public void setFirstName(String firstName) {
    this.firstName = firstName;
  }

  public String getLastName() {
    return lastName;
  }

  public void setLastName(String lastName) {
    this.lastName = lastName;
  }

  public String getStreetAddress() {
    return streetAddress;
  }

  public void setStreetAddress(String streetAddress) {
    this.streetAddress = streetAddress;
  }

  public String getCityState() {
    return cityState;
  }

  public void setCityState(String cityState) {
    this.cityState = cityState;
  }

  public String getZipCode() {
    return zipCode;
  }

  public void setZipCode(String zipCode) {
    this.zipCode = zipCode;
  }

}

Answer 1

switch语句并非真正用于ArrayList。。我很确定它只做整数，现在在新版本的Java字符串中。我建议改用for（）语句。。。。不确定您还将在其他地方使用该开关，但要有创意：）