未定义的属性：Illumb\Database\Eloquent\Relations\BelongsTo:：$name laravel 5.4

Question

嗨，下面是我的亲戚

用户模型

   public function loginlogout()
    {
        $this->HasMany("App\Models\LoginLogoutLogs");
    }

这是我的LoginLogs模型

  public function users()
    {
        return $this->belongsTo('App\Models\User');
    }

我试图访问名称从用户这样

 $loginLogoutLogs = LoginLogoutLogs::all();
        foreach($loginLogoutLogs as $loginLogoutLog){
            dd($loginLogoutLog->users()->name);
        }

但我得到了这个错误

未定义的属性：照亮\数据库\雄辩\关系\属于::$name

编辑添加模型

<?php

namespace App\Models;

use Illuminate\Notifications\Notifiable;
use Illuminate\Foundation\Auth\User as Authenticatable;
use Zizaco\Entrust\Traits\EntrustUserTrait;
use Session;
use Illuminate\Support\Facades\DB;

class User extends Authenticatable
{
    use Notifiable;
    use EntrustUserTrait;

    protected $table = 'tbl_users';
    protected $primaryKey = 'id';
    protected $guarded = ['id'];
    const API = 'api';
    const WEB = 'web';

    /**
     * The attributes that are mass assignable.
     *
     * @var array
     */
    protected $fillable = [
        'name', 'email', 'password', 'last_login', 'Address', 'Age', 'DateOfBirth', 'created_by', 'deleted_by'
    ];

    /**
     * The attributes that should be hidden for arrays.
     *
     * @var array
     */
    protected $hidden = [
        'password', 'remember_token',
    ];

    protected $casts = [
        'is_admin' => 'boolean',
    ];

    public function isAdmin()
    {
        return $this->is_admin;
    }

    static function GetUserNamebyID($id)
    {
        $name = User::select("name")->where(["id" => $id])->pluck('name');
        if (isset($name[0])) {
            return $name[0];
        } else {
            return '';
        }
    }



    public function loginlogout()
    {
        $this->HasMany("App\Models\LoginLogoutLogs", 'userID');
    }

    public function company()
    {
        $this->HasMany("App\Models\Company");
    }
}

现在是LoginLogout模型

<?php


namespace App\Models;

use Illuminate\Notifications\Notifiable;
use Zizaco\Entrust\Traits\EntrustUserTrait;
use Illuminate\Database\Eloquent\Model;
use Session;
use Illuminate\Support\Facades\DB;

class LoginLogoutLogs extends Model
{
    use Notifiable;
    use EntrustUserTrait;

    protected $table = 'tbl_users_logs';
    protected $primaryKey = 'id';
    protected $guarded = ['id'];
    const API = 'api';
    const WEB = 'web';


    /**
     * The attributes that are mass assignable.
     *
     * @var array
     */
    protected $fillable = [
        'userID','is_accpeted','type','addedFrom'
    ];

    /**
     * The attributes that should be hidden for arrays.
     *
     * @var array
     */
    protected $hidden = [
        'password', 'remember_token',
    ];

    protected $casts = [
        'is_admin' => 'boolean',
    ];

    public function isAdmin()
    {
        return $this->is_admin;
    }

    // change company to hasmany

    public function user()
    {
        return $this->belongsTo('App\Models\User');
    }

}

Answer 1

您需要更改您与用户的关系，在LoginLogoutLogs中添加外键：

public function user()
{
    return $this->belongsTo('App\Models\User', 'userID');
}

还要确保调用用户insted的用户

$loginLogoutLogs = LoginLogoutLogs::all();
foreach($loginLogoutLogs as $loginLogoutLog){
    dd($loginLogoutLog->user->name);
}

如果要执行“快速加载”，请使用：

$loginLogoutLogs = LoginLogoutLogs::with('user')->get();
foreach($loginLogoutLogs as $loginLogoutLog){
    dd($loginLogoutLog->user->name);
}

Answer 2

简单修复：

$loginLogoutLogs = LoginLogoutLogs::all();
foreach($loginLogoutLogs as $loginLogoutLog){
    dd($loginLogoutLog->users->name);
}

您希望访问关系实体，而不是关系模型。

通过使用users（），您的代码认为您试图在users模型上调用name（）方法，而不是在loginLogs类上调用users方法。

Answer 3

简单地改变你的部分

dd($loginLogoutLog->users()->name);

成

dd($loginLogoutLog->users->name);

拆下用户的支架，这很容易修复。这里我们得到的是一个属性，而不是一个函数。。。。（尽管在模型中定义为功能）