使用带有spring LDAP API的LDAP进行身份验证，而不使用spring security

Question

 <ldap-server id="ldapServer"
                 url="ldap://ad.company.com:389"
                 manager-dn="CN=serviceaccount,OU=Service Accounts,DC=ad,DC=company,DC=com"
                 manager-password="password"/>

    <authentication-manager>
        <ldap-authentication-provider
                server-ref="ldapServer"
                user-search-base="dc=ad,dc=company,dc=com"
                user-search-filter="sAMAccountName={0}"
                group-search-filter="member={0}"
                group-search-base="ou=Groups,dc=ad,dc=company,dc=com"
                group-role-attribute="cn"/>
    </authentication-manager>

import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.ldap.core.LdapTemplate;
import org.springframework.ldap.core.support.LdapContextSource;
import org.springframework.ldap.authentication.DefaultValuesAuthenticationSourceDecorator;

@Configuration
public class LdapConfiguration {

    @Bean
    public LdapContextSource contextSource(){
        LdapContextSource contextSource = new LdapContextSource();

        contextSource.setUrl("ldap://ad.company.com:389");
        contextSource.setBase("DC=ad,DC=company,DC=com");
        contextSource.setUserDn("CN=serviceaccount,OU=Service Accounts,DC=ad,DC=company,DC=com");
        contextSource.setPassword("password");
        contextSource.afterPropertiesSet();
        return contextSource;
    }


    @Bean
    public LdapTemplate ldapTemplate(){

        LdapTemplate template = new LdapTemplate(contextSource());
        try {
            template.afterPropertiesSet();
        } catch (Exception e) {
            e.printStackTrace();
        }
        return template;
    }
}

 AndFilter filter = new AndFilter();

    filter.and(new EqualsFilter("sAMAccountName", userloginName));

    return ldapTemplate.authenticate("OU=Service Accounts", filter.encode(), userPassword);

No results found for search, base: 'OU=Service Accounts'; filter: '(sAMAccountName=usernameIinput)'.

group-search-filter="member={0}"
group-search-base="ou=Groups,dc=ad,dc=company,dc=com"
group-role-attribute="cn"/>

Answer 1

我想通了。

使用LDAPTemplate的//LDAP连接

@Configuration
public class LdapConfiguration {

    @Bean
    public LdapContextSource contextSource(){
        LdapContextSource contextSource = new LdapContextSource();
        contextSource.setUrl("ldap://companyurl.com:389");
        contextSource.setUserDn("CN=serviceaccount,OU=Service Accounts,DC=ad,DC=company,DC=com");
        contextSource.setPassword("secretpassword");
        return contextSource;
    }

    @Bean
    public LdapTemplate ldapTemplate(){
        LdapTemplate template = new LdapTemplate(contextSource());
        return template;
    }
}

//身份验证部分

AndFilter filter = new AndFilter();
filter.and(new EqualsFilter("mailNickname", username));

Boolean authenticate = ldapTemplate.authenticate(base, filter.encode(), userpassword);