如何连接两个hashmap值？

Question

这是我制作的hashmap（Ik它不是最好的，也没有太多的逻辑），我想知道如果用户输入像“DVIII”这样的数据，其中“d”的值为“500”，“viii”的值为“8”，然后将它们打印为DVIII=5008，那么如何连接hashmap的值

import java.util.Scanner;
import java.util.HashMap;

public class Main{
    public static void main(String args[]){
         
HashMap<String, String> Roman = new HashMap<String, String>();
        Roman.put("I","One");
        Roman.put("II","Two");
        Roman.put("III","Three");
        Roman.put("IV","Four");
        Roman.put("V","Five");
        Roman.put("VI","Six");
        Roman.put("VII","Seven");
        Roman.put("VIII","Eight");
        Roman.put("IX","Nine");
        Roman.put("X","Ten");
        Roman.put("XI","Eleven");
        Roman.put("XII","Twelve");
        Roman.put("XIII","Thirteen");
        Roman.put("XIV","Fourteen");
        Roman.put("XV","Fifteen");
        Roman.put("XVI","Sixteen");
        Roman.put("XVII","Seventeen");
        Roman.put("XVIII","Eighteen");
        Roman.put("XIX","Nineteen");
        Roman.put("XX","Twenty");
        Roman.put("XXX","Thirty");
        Roman.put("XL","Fourty");
        Roman.put("L","Fifty");
        Roman.put("LX","Sixty");
        Roman.put("LXX","Seventy");
        Roman.put("LXXX","Eighty");
        Roman.put("XC","Ninety");
        Roman.put("C","One Hundred");
        Roman.put("CC","Two Hundred");
        Roman.put("CCC","Three Hundred");
        Roman.put("CD","Four Hundred");
        Roman.put("D","Five Hundred");
        Roman.put("DC","Six Hundred");
        Roman.put("DCC","Seven Hundred");
        Roman.put("DCCC","Eight Hundred");
        Roman.put("CM","Nine Hundred");
        Roman.put("M","One Thousand");
        Roman.put("MM","Two Thousand");
        Roman.put("MMM","Three Thousand");
        Roman.put("MMMM","Four Thousand");
        
        Scanner Input = new Scanner(System.in);
        System.out.print("\nEnter a Roman Numeral: ");
        String RomanNumeral = Input.nextLine();
        
        System.out.print("\n The equivalent of the Roman numeral "+RomanNumeral+" is " + Roman.get(RomanNumeral));
    }
}

Answer 1

首先，你的问题可以用算法解决，正如Emil所说，我认为定义静态值来解析罗马数字是不可行的。例如，在代码中，您没有指定字符串的长度以将其视为有效数字，并且无法区分符号的不同排列之间的差异。

示例：

如果一次转换一个字符:div将转换为[500,1,5]。

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