用Java Process Builder启动GitLog

Question

public void createGitLog( Path path ) {
            try
            {          
                String gitpath = "--git-dir=C:/Users/User/Code/code1/git/.git";
                String options = "--pretty=format:\"%H \\\"%an\\\" %ad \\\"%s\\\"\" --numstat --date=short";

                ProcessBuilder builder = new ProcessBuilder("git", gitpath, "log", options );
                Process process = builder.start();

                builder.redirectOutput(ProcessBuilder.Redirect.to( path.resolve("gitlog.dat").toFile() ) );

                int exitValue = process.waitFor();

                if ( exitValue != 0 )
                {
                    // throw
                }
            }
            catch (IOException e) {

            } 
}

如果我在cmd中尝试这个命令，它可以工作，但在Java中，我得到的总是exitcode128。

这个过程有什么问题？

Answer 1

在我的情况下，在终端中运行命令的工作原理是：

“/bin/bash”-bash的路径

“-c”-表示下一个参数是命令

String command = "git " + gitpath + " log " + options;
ProcessBuilder builder = new ProcessBuilder("/bin/bash" , "-c" , command);

 .directory(new File("C:/Users/User/Code/code1/git/"))