Java Spring如何模拟实现相同接口的bean

Question

我创建了一个bean，如下所示

@Profile({"test", "dev", "int"})
@Bean
public CustomerEmailSenderImpl customerEmailSenderImpl(){
    return new CustomerEmailSenderImpl ();
}

在一个测试类中，我模拟该类如下：

   @ActiveProfiles(profiles = {"test"})
   .....
    @MockBean
    private CustomerEmailSenderImpl customerEmailSenderImpl;

@Profile({"dev", "int"})
@Bean(name = "customerEmailSender")
public CustomerEmailSender customerEmailSenderImpl1(){
    return new CustomerEmailSenderImpl1 ();
}

@Profile({"test"})
@Bean(name = "customerEmailSender")
public CustomerEmailSender customerEmailSenderImpl2(){
    return new CustomerEmailSenderImpl2 ();
}

@ActiveProfiles(profiles = {"test"})
...
@MockBean
private CustomerEmailSender customerEmailSender;

应用程序在没有错误的情况下启动。但是测试并没有模仿bean CustomerEmailSenderImpl2。bean总是被实例化，并执行真正的代码。即使在测试类中从接口到类名的更改也没有帮助：

@MockBean
private CustomerEmailSenderImpl2 customerEmailSenderImpl2;

需要什么来模拟bean CustomerEmailSenderImpl2？

Answer 1

解决方案是使用@qualifier，然后在测试类中使用qualifier名称作为变量名称。

@Profile({"test"})
@Bean(name = "customerEmailSender")
@Qualifier(value="customerEmailSenderImpl2")
public CustomerEmailSender customerEmailSenderImpl2(){
    return new CustomerEmailSenderImpl2 ();
}



@MockBean
private CustomerEmailSender customerEmailSenderImpl2;