CI:用户注册表的主详细信息不起作用

Question

我想创建一个用户注册表单，在这里，我允许用户可以像谷歌联系人一样，随意放置电子邮件和电话。

我已经创建了一个表单，允许用户动态添加或删除电子邮件和电话的输入字段。这是它的图像：用户注册表

这是我使用的模型脚本。。

public function store_email() {
        if (! $this->validate_email()) return FALSE;
        $this->db->trans_begin();
        try {
            $this->db->insert($this->table_user, $this);
            $id = $this->db->insert_id();
            foreach ($this->email as $key => $value) $this->email[$key]['user_id'] = $id;
            $this->db->insert_batch($this->table_email, $this->email);
        } catch (Exception $e) {
            return FALSE;
        }
        if ($this->db->trans_status() === FALSE)
        {
            $this->db->trans_rollback();
            return FALSE;
        } else {
            $this->db->trans_commit();
            return TRUE;
        }
    }
public function store_phone() {
        if (! $this->validate_phone()) return FALSE;
        $this->db->trans_begin();
        try {
            $this->db->insert($this->table_user, $this);
            $id = $this->db->insert_id();
            foreach ($this->phone as $key => $value) $this->phone[$key]['user_id'] = $id;
            $this->db->insert_batch($this->table_phone, $this->phone);
        } catch (Exception $e) {
            return FALSE;
        }
        if ($this->db->trans_status() === FALSE)
        {
            $this->db->trans_rollback();
            return FALSE;
        } else {
            $this->db->trans_commit();
            return TRUE;
        }
    }

这是我使用的控制器脚本...

public function store() {

        $this->model->first_name = $this->input->post('first_name', TRUE);
        $this->model->middle_name = $this->input->post('middle_name', TRUE);
        $this->model->last_name = $this->input->post('last_name', TRUE);
        $this->model->email = [];
        $this->model->phone = [];

        foreach ($this->input->post('label_id', TRUE) as $key => $value) $this->model->email[$key]['label_id'] = $value;
        foreach ($this->input->post('email', TRUE) as $key => $value) $this->model->email[$key]['email'] = $value;
        foreach ($this->input->post('label_id', TRUE) as $key => $value) $this->model->phone[$key]['label_id'] = $value;
        foreach ($this->input->post('phone', TRUE) as $key => $value) $this->model->phone[$key]['phone'] = $value;

        if ($this->model->store_email() === TRUE) {
            if ($this->model->store_phone() === TRUE) {
                $notification = 'Register success! You may login now!';
            } else {
                $notification = 'Register fail!';
            }
        } else {
            $notification = 'Register fail!';
        }

        $this->CI->session->set_flashdata('Success',$notification);
        redirect(base_url().'login');

    }

我运行这个代码，它给我错误说数组到字符串转换，我不能存储任何数据到数据库。

更新：

下面是我得到的错误：

A PHP Error was encountered

Severity: Notice

Message: Array to string conversion

Filename: database/DB_query_builder.php

Line Number: 1496

Backtrace:

File: C:\xampp\htdocs\ci-master-detail-trans\application\models\Customer_model.php
Line: 103
Function: insert_batch

File: C:\xampp\htdocs\ci-master-detail-trans\application\controllers\Customer.php
Line: 50
Function: store

File: C:\xampp\htdocs\ci-master-detail-trans\index.php
Line: 292
Function: require_once

我用于此目的的表格：

• 表\u用户（id、姓名、用户名、密码）

Answer 1

在批处理插入代码之前添加此行

 $phone_details = implode(',',$this->phone);

然后在批插入中进行如下更改

 $this->db->insert_batch($this->table_phone, $phone_details); // phone number will be stored in , separated format i.e. 1234567890,3216549870 

Answer 2

对于数组到字符串的转换错误，可以按如下方式使用内爆函数：

 $string_version = implode(',', $original_array)

请编辑你的文章，并把整个错误，以便我们可以帮助你。