无法通过python发送电子邮件（gmail）

Question

我有一个代码，就像半年前一样工作。它基本上发送电子邮件。

import smtplib
import socket

gmail_user="SENDERMAIL"
gmail_password="SENDERPASS"
to = 'SENDTOTHIS'

email_text = "ADSADSADSA"

try:
    server = smtplib.SMTP_SSL('smtp.gmail.com', 465)
    server.ehlo()
    server.login(gmail_user, gmail_password)
    server.starttls()
    server.sendmail(gmail_user, to, email_text)
    server.close()

    #I was using this code below and it was working. I tried above code but it also did not work.
    #server = smtplib.SMTP("smtp.gmail.com:587")
    #server.ehlo()
    #server.starttls()
    #server.ehlo()
    #server.login(gmail_user, gmail_password)
    #server.sendmail(gmail_user, to, email_text)
    #server.close()
    print("Done")
except Exception as exception:
    print(exception)

这是例外

（534， b'5.7.14

5.7.14 KL7\u 2qGSLW9IBjP8dKKgP67bEgyKNc5ls76dnVDZcUlVQjJUQb0JX9BIVi\u Agb84vKNOKB

5.7.14fshB0ngZ_Tn8ocDpDHKavRKXmluVjHo5YM7ADKENtWn4aVTxyvaBlbXRGpA1EBh91bdV-o

5.7.14 PWIAWUXKMRQEUNSIFCV68DP4A7GHIU9YKNTYQTUEHGD4HGKTXA4JZ0MHSQDJD13UQWYB

5.7.14-YLE5SD2H5YXN8KKSAK-J\U HXMBPY7WNYECOV8LQ1AA3SPZGO

5.7.14请使用web浏览器，然后重试。

5.7.14了解更多信息

5.7.14https://support.google.com/mail/answer/78754f132-v6sm3660398wme.24-gsmtp'）

我确实试过

• 登录的gmail
• 将设备添加到受信任的设备
• 通过gmail打开IMAP
• 让不太安全的应用程序
• 尝试了这个：

https://support.google.com/mail/answer/7126229?visit_id=636711453029417344-336837064

Answer 1

我还建议使用一个更简单的库（smtplib之上的包装器，以确保不涉及其他因素）。。。。比如yagmail（免责声明：我是开发人员）。

尝试看看这是否有效：

import yagmail
yag = yagmail.SMTP("username", "password")
yag.send(subject="hi")

Answer 2

有很多方法可以解决这个问题。我希望这段代码有帮助。您唯一需要做的就是填充所需的变量。

    import socket
    import smtplib
    from email.mime.multipart import MIMEMultipart
    from email.mime.text import MIMEText
    # 
    message = "Your message" # Type your message
    msg = MIMEMultipart()
    password = "********" # Type your password 
    msg['From'] = "[e-mail]" # Type your own gmail address 
    msg['To'] = "[e-mail]" # Type your friend's mail address  
    msg['Subject'] = "title" # Type the subject of your message 
    msg.attach(MIMEText(message, 'plain'))
    server = smtplib.SMTP('smtp.gmail.com: 587')
    server.starttls()
    server.login(msg['From'], password)
    server.sendmail(msg['From'], msg['To'], msg.as_string())
    server.quit()