如何在不和谐中创建动态聊天。js机器人？

Question

有了这个，我的意思是像角色机器人一的反应这样的聊天：当你执行命令rr！为了创建一个新的反应角色，它要求您输入一个通道，在您在一个全新的消息中回答后，机器人的消息被编辑，您必须在另一个新消息中回答新问题。这怎么可能呢？我希望我已经正确地解释了自己。谢啦




Answer 1

从某种意义上说，实现这一点的方法是为bot读取消息的每个通道保持一个“状态”。其想法是，每当BOT从某个频道获得新消息时，它首先检查它是否已经在会话的中间。根据此状态的值和输入，bot将执行相应的操作。

var state = 0;

//on rr!reactionrole
{
switch(state) {
 case 0: //start the conversation and change the state to 1; break;
 case 1: //continue the conversation, edit the message, set state to 2; break;
 //other cases
}
}

Answer 2

不一致js有一种方法可以用于此目的，MessageCollector。一旦您将其设置为textconnel，它将根据CollectorFilter和MessageCollectorOptions收集消息。

也就是说，要获得答案，但要无缝编辑原始问题消息，只需在存储的消息ID方法上使用消息#edit（）。

例如：

const questions = ['What role?', 'What message?', 'What emoji?'];

const question = await message.channel.send(questions[0]); // store the question message object to a constant to be used later

const filter = msg => msg.author.id === message.author.id; // creates the filter where it will only look for messages sent by the message author
const collector = message.channel.createMessageCollector(filter, { time: 60 * 1000 }); // creates a message collector with a time limit of 60 seconds - upon that, it'll emit the 'end' event

const answers = []; // basic way to store to the answers, for this example

collector.on('collect', msg => { // when the collector finds a new message
  answers.push(msg.content);
  questions.shift();
  if (questions.length <= 0) return collector.stop('done'); // sends a string so we know the collector is done with the answers
  question.edit(questions[0]).catch(error => { // catch the error if the question message was deleted - or you could create a new question message
    console.error(error);
    collector.stop();
  });
});

collector.on('end', (collected, reason) => {
  if (reason && reason === 'stop') {
    // when the user has answered every question, do some magic
  }
  message.channel.send('You did not answer all the questions in time or the original message was deleted!');
});

注意：我还没有测试过这个，它的制作也不是很好，但是你应该能够根据自己的使用来调整它。我建议阅读这本指南，它将解释更多关于异步收集器和更多有趣的东西！