使用改型没有得到正确的错误体响应

Question

{
"status": 401,
"data": false,
"message": "User login unsuccessful.",
"user_msg": "Email or password is wrong. try again"
}

override fun onResponse(
                    call: Call<LoginResponse>,
                    response: Response<LoginResponse>
                ) {
                    var res = response

                    Log.d("response check ", "" + response.body()?.status.toString())
                    if (res.body()?.status==200) {

                        SharedPrefManager.getInstance(applicationContext)
                            .saveUser(response.body()?.data!!)

                        val intent = Intent(applicationContext, HomeActivity::class.java)
                        intent.flags =
                            Intent.FLAG_ACTIVITY_NEW_TASK or Intent.FLAG_ACTIVITY_CLEAR_TASK
                        Toast.makeText(
                            applicationContext,
                            res.body()?.message,
                            Toast.LENGTH_LONG
                        ).show()
                        Log.d("kjsfgxhufb",response.body()?.status.toString())
                        startActivity(intent)
                        finish()


                    }

            else
                    {
                        try {
                            val jObjError =
                                JSONObject(response.errorBody()!!.string())
                            Toast.makeText(
                                applicationContext,
                                jObjError.getJSONObject("user_msg").getString("message"),
                                Toast.LENGTH_LONG
                            ).show()
                        } catch (e: Exception) {
                           Toast.makeText(applicationContext, e.message, Toast.LENGTH_LONG).show()
                        }
                    }

我的输出是吐司：

Value Email or password is wrong. try again at user_msg of type java.lang.String cannot be 
converted to JSONObject

事实上，我不想吐司错误味精像这样…我想简单的信息像“电子邮件或密码是错误的。再试一次”

帮帮我谢谢

Answer 1

因此，您试图从“user_msg”中获取JSONObject，这是不可能的，因为“user_msg”不是JSONObject，而是一个字符串。

JSONObject如下所示：

"user_msg": {
   "message": "Your error"
}

但事实并非如此，您得到的是两个不同的字符串值。

"user_msg": "message",
"message" : "another message"