Discord bot发送不需要的消息

Question

我有一个警告脚本，你基本上警告duh，它工作，但每次它发送一个不需要的消息

这是我的剧本

const db = require("quick.db")
execute(message, args, prefix){
    if(!message.mentions.users.first())
    {
        message.channel.send("Please specify a user to warn")
        return;
    }
    if(args[1]){
        if(args[1].startsWith("<")){
        message.channel.send("You can only warn one person at a time")
        return;
        }
    }
    if(!args[1]){
        message.channel.send("Please specify a reson for the warn")
        return;
    }
    let warned = message.guild.member(message.mentions.users.first())
    message.channel.send(`${message.mentions.users.first}` + "You have been `warned` for " + args.slice(1).join(' '))
    if(!db.get(`WCount_${message.guild.id}_${warned}`)){
    db.set(`WCount_${message.guild.id}_${warned}`, 1)
    }else if(db.get(`WCount_${message.guild.id}_${warned}`)){
        db.set(`WCount_${message.guild.id}_${warned}`,db.get(`WCount_${message.guild.id}_${warned}`) + 1 )
    }
    message.channel.send(`${message.mentions.users.first()}, You now have ${db.get(`WCount_${message.guild.id}_${warned}`)} warns!`)
}

我很确定这是一个错误，但我只是想确定我在这里问过它，任何帮助都是感激的

Answer 1

在下一行中，您编写了消息。提到。用户。首先，您要附加实际函数的代码，而不是调用它：

message.channel.send(`${message.mentions.users.first}` + "You have been `warned` for " + args.slice(1).join(' '))

您需要在函数后添加括号，以确保调用该函数：

message.channel.send(`${message.mentions.users.first()}` + "You have been `warned` for " + args.slice(1).join(' '))