颤振如何将表单数据传递到api

Question

我有一个表单来获取用户的数据。目标是将表单数据作为对象传递给Api。表格如下。

    Form(
                  key: _formKey,
                  child: Column(
                    children: [
     Seperator(),
                      TextField(
                        decoration: const InputDecoration(
                          hintText: 'Add a title',
                        ),
                      ),
                      Seperator(),
                      TextField(
                        decoration: const InputDecoration(
                          hintText: 'Add a description',
                        ),
                      ),
                      Seperator(),
    TextField(
                        decoration: const InputDecoration(
                          hintText: 'Add a Price',
                        ),
                      ),
                      Seperator(),
                      TextField(
                        decoration: const InputDecoration(
                          hintText: 'Select Unit',
                        ),
                      ),
Button(
                    isProcessing: isProcessing,
                    name: 'Create Post',
                    onPressed: () {
                      final formdata = _formKey.currentState!.save();
                      createpost(formdata); // Api Function
                    },
]

// Api Function
    createpost(AddPost formdata) async {
        try {
          final service = PostService();
          final response =
              await service.createpost(formdata);
        } catch (error) {
          setErrorMessage(error.toString());
        }

如何将表单数据作为对象传递给Api函数？

Answer 1

您也可以使用这个包传递表单数据

var dio = Dio();
 var formData = FormData.fromMap({
 'name': 'wendux',
  'age': 25,
  'file': await MultipartFile.fromFile('./text.txt',filename: 
 'upload.txt')
 });
  var response = await dio.post('/info', data: formData);