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问题：

Android中的错误“只有创建视图层次结构的原始线程才能接触其视图”[重复]

谢昊乾
2023-03-14

我正在使用Android和PHP创建一个简单的登录应用程序，但我遇到了一个错误，有人能帮我吗？我正在尝试在Android作为客户端和PHP/MySQL作为服务器端之间建立关系，但仍然没有成功得到响应。

package com.sencide;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.List;

import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;
import org.apache.http.protocol.HTTP;
import org.apache.http.util.EntityUtils;

import android.os.Bundle;
import android.os.StrictMode;
import android.app.Activity;
import android.util.Log;
import android.view.Menu;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;

public class AndroidLogin extends Activity implements OnClickListener {


     Button ok,back,exit;
     TextView result;


    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);


        StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
        StrictMode.setThreadPolicy(policy);

     // Login button clicked
        ok = (Button)findViewById(R.id.btn_login);
        ok.setOnClickListener(this);

        result = (TextView)findViewById(R.id.lbl_result);



    }



    public void postLoginData() {
        // Create a new HttpClient and Post Header
        HttpClient httpclient = new DefaultHttpClient();
         Log.e("Responce-->","after httpclient");
        /* login.php returns true if username and password is equal to saranga */
        HttpPost httppost = new HttpPost("http://10.0.2.2/login.php");
        Log.e("Responce-->","after httppost");
        try {
            // Add user name and password
         EditText uname = (EditText)findViewById(R.id.txt_username);
         String username = uname.getText().toString();

         EditText pword = (EditText)findViewById(R.id.txt_password);
         String password = pword.getText().toString();

            List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
            nameValuePairs.add(new BasicNameValuePair("username", username));
            nameValuePairs.add(new BasicNameValuePair("password", password));
            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
            Log.e("Responce-->","after using the list name pair");

            // Execute HTTP Post Request
            Log.w("SENCIDE", "Execute HTTP Post Request");
            HttpResponse response = httpclient.execute(httppost);
            Log.e("Responce-->","after execute the http response");
          //  String str = inputStreamToString(response.getEntity().getContent()).toString();
            String str = EntityUtils.toString(response.getEntity(), HTTP.UTF_8);
            //Log.w("SENCIDE", str);

            Log.e("Responce-->",""+str);

            if(str.toString().equalsIgnoreCase("true"))
            {
             Log.w("SENCIDE", "TRUE");
             result.setText("Login successful");  
            }else
            {
             Log.w("SENCIDE", "FALSE");
             result.setText(str);            
            }

        } catch (ClientProtocolException e) {
         e.printStackTrace();
        } catch (IOException e) {
         e.printStackTrace();
        }
    } 



    private StringBuilder inputStreamToString(InputStream is) {
        String line = "";
        StringBuilder total = new StringBuilder();
        // Wrap a BufferedReader around the InputStream
        BufferedReader rd = new BufferedReader(new InputStreamReader(is));
        // Read response until the end
        try {
         while ((line = rd.readLine()) != null) {
           total.append(line);
         }
        } catch (IOException e) {
         e.printStackTrace();
        }
        // Return full string
        return total;
       }

        /* login.php returns true if username and password is equal to test1 */


    @Override
    public void onClick(View view) {
        // TODO Auto-generated method stub
        final String resultText;
        if(str.toString().equalsIgnoreCase("true")) {
            resultText = "Login successful";
        }else {
            resultText = str;
        }

        if(view == ok){
             Thread t = new Thread(){


                    public void run(){
                        postLoginData();

                        result.post(new Runnable() {
                            public void run() {
                                result.setText(resultText);
                            }
                        });
                    }
                };
                t.start();

          }
    }





}

   04-04 19:04:20.504: E/Responce-->(457): after httpclient
04-04 19:04:20.517: E/Responce-->(457): after httppost
04-04 19:04:20.544: E/Responce-->(457): after using the list name pair
04-04 19:04:20.544: W/SENCIDE(457): Execute HTTP Post Request
04-04 19:04:20.824: E/Responce-->(457): after execute the http response
04-04 19:04:20.834: E/Responce-->(457): true
04-04 19:04:20.834: W/SENCIDE(457): TRUE
04-04 19:04:20.844: W/dalvikvm(457): threadid=9: thread exiting with uncaught exception (group=0x40015560)
04-04 19:04:20.912: E/AndroidRuntime(457): FATAL EXCEPTION: Thread-10
04-04 19:04:20.912: E/AndroidRuntime(457): android.view.ViewRoot$CalledFromWrongThreadException: Only the original thread that created a view hierarchy can touch its views.
04-04 19:04:20.912: E/AndroidRuntime(457):  at android.view.ViewRoot.checkThread(ViewRoot.java:2932)
04-04 19:04:20.912: E/AndroidRuntime(457):  at android.view.ViewRoot.requestLayout(ViewRoot.java:629)
04-04 19:04:20.912: E/AndroidRuntime(457):  at android.view.View.requestLayout(View.java:8267)
04-04 19:04:20.912: E/AndroidRuntime(457):  at android.view.View.requestLayout(View.java:8267)
04-04 19:04:20.912: E/AndroidRuntime(457):  at android.view.View.requestLayout(View.java:8267)
04-04 19:04:20.912: E/AndroidRuntime(457):  at android.view.View.requestLayout(View.java:8267)
04-04 19:04:20.912: E/AndroidRuntime(457):  at android.view.View.requestLayout(View.java:8267)
04-04 19:04:20.912: E/AndroidRuntime(457):  at android.widget.TextView.checkForRelayout(TextView.java:5521)
04-04 19:04:20.912: E/AndroidRuntime(457):  at android.widget.TextView.setText(TextView.java:2724)
04-04 19:04:20.912: E/AndroidRuntime(457):  at android.widget.TextView.setText(TextView.java:2592)
04-04 19:04:20.912: E/AndroidRuntime(457):  at android.widget.TextView.setText(TextView.java:2567)
04-04 19:04:20.912: E/AndroidRuntime(457):  at com.sencide.AndroidLogin$1.run(AndroidLogin.java:136)
04-04 19:04:23.464: I/Process(457): Sending signal. PID: 457 SIG: 9

<?php
$host="localhost"; // Host name
$username="root"; // Mysql username
$password="root"; // Mysql password
$db_name="testlogin"; // Database name
$tbl_name="members"; // Table name

// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");

// username and password sent from form
$myusername=$_POST['username'];
$mypassword=$_POST['password'];

// To protect MySQL injection
$myusername = stripslashes($myusername);
$mypassword = stripslashes($mypassword);
$myusername = mysql_real_escape_string($myusername);
$mypassword = mysql_real_escape_string($mypassword);

$sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'";
$result=mysql_query($sql);

// Mysql_num_row is counting table row
$count=mysql_num_rows($result);

// If result matched $myusername and $mypassword, table row must be 1 row
if($count==1){
echo "true";
}
else {
echo "Login Failed";
}
?>

共有3个答案

穆锋
2023-03-14

您不能在主UI线程外更改android视图。在您的示例中，您正在启动一个新线程并在其上运行postLoginData（）。由于postLoginData还设置textview的文本，因此会出现此错误。

您应该：在新线程上执行超文本传输协议请求，然后在UI线程上更改文本。

有多种方法可以做到这一点。

  • 异步任务
  • 处理程序

这个超级简单但可能不建议的方法只是让你站起来。只要你在UI的新线程中进行更改，你就会想这样做，所以在本例中，当你设置结果的文本时。

result.post(new Runnable() {
        public void run() {
            result.setText(str);
        }
    });
}

这将在UI线程上运行。你真的应该先看看我发布的两个选项，否则你会遇到更多的麻烦。

**编辑**您只需替换此代码即可在主线程而不是新线程上发布。

if(str.toString().equalsIgnoreCase("true"))
{
 Log.w("SENCIDE", "TRUE");
 result.setText("Login successful");  
}else
{
 Log.w("SENCIDE", "FALSE");
 result.setText(str);            
}

让它看起来像这样：

final String resultText;
if(str.toString().equalsIgnoreCase("true")) {
    resultText = "Login successful";
}else {
    resultText = str;
}
result.post(new Runnable() {
        public void run() {
            result.setText(resultText);
        }
    });
}
冷正信
2023-03-14

好吧，我对你的代码做了一些修改，它仍然很丑，需要大量的重构，但是告诉我它是否会引发任何异常。

编辑：将传递给请求的用户名和密码作为参数添加到您的postLoginData（字符串密码，字符串用户名）方法。应该可以了。

import java.io.IOException;
import java.util.ArrayList;
import java.util.List;

import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;
import org.apache.http.protocol.HTTP;
import org.apache.http.util.EntityUtils;

import android.os.Bundle;
import android.os.StrictMode;
import android.app.Activity;
import android.util.Log;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;

public class AndroidLogin extends Activity implements OnClickListener {


    Button ok, back, exit;
    TextView result;
    EditText uname;
    EditText pword;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);


        StrictMode.ThreadPolicy policy = 
        new StrictMode.ThreadPolicy.Builder().permitAll().build();
        StrictMode.setThreadPolicy(policy);

        // Login button clicked
        ok = (Button) findViewById(R.id.btn_login);
        ok.setOnClickListener(this);
        uname = (EditText) findViewById(R.id.txt_username);
        pword = (EditText) findViewById(R.id.txt_password);
        result = (TextView) findViewById(R.id.lbl_result);


    }

    @Override
    public void onClick(View view) {
        // TODO Auto-generated method stub
        final String resultText;   

        final String username = uname.getText().toString();           
        final String password = pword.getText().toString();


        if (view == ok) {
            Thread t = new Thread() {

                public void run() {
                    postLoginData(username,password);
                }
            };
            t.start();

        }
    }

    private void postLoginData(String username,String password) {

        try {
            // Create a new HttpClient and Post Header
            HttpClient httpclient = new DefaultHttpClient();
            Log.e("Response-->", "after httpclient");
        /* login.php returns true if username and password is equal to saranga */
            HttpPost httppost = new HttpPost("http://10.0.2.2/login.php");
            Log.e("Response-->", "after httppost");


            List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
            nameValuePairs.add(new BasicNameValuePair("username", username));
            nameValuePairs.add(new BasicNameValuePair("password", password));

            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
            Log.e("Responce-->", "after using the list name pair");

            // Execute HTTP Post Request
            Log.w("SENCIDE", "Execute HTTP Post Request");
            HttpResponse response = httpclient.execute(httppost);
            Log.e("Responce-->", "after execute the http response");
            String str = EntityUtils.toString(response.getEntity(), HTTP.UTF_8);

            if (str.toString().equalsIgnoreCase("true")) {

                runOnUiThread(new Runnable() {
                    public void run() {
                        result.setText("Login Successful");

                    }
                });


            } else {
                runOnUiThread(new Runnable() {
                    public void run() {
                        result.setText("Duh");

                    }
                });
            }

        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

    }


}
潘嘉佑
2023-03-14

解决方案在logcat的日志中：

04-04 18:38:47.596: E/AndroidRuntime(413): android.view.ViewRoot$CalledFromWrongThreadException: Only the original thread that created a view hierarchy can touch its views.

发布用户/密码正在工作。您可以获得“true”响应，但随后您尝试在线程外部创建的视图中设置标签或类似内容。这是禁忌。

result.setText("Login successful");

看看关于如何从其他线程更新视图的线程/进程的AndroidSDK文档：http://developer.android.com/guide/components/processes-and-threads.html

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