将具有断点的字符串转换为数组

Question

我有一个与PHP链接的JavaScript AJAX。PHP有以下代码：

while ($row = $req->fetch(PDO::FETCH_BOTH)) {
    $ajaxArray[] = $row[0];
    $ajaxArray[] = $row[1];
    $ajaxArray[] = $row[2];
    $ajaxArray[] = $row[3];
}

foreach ($ajaxArray as $val) {
    echo $val;
    echo "#";
}

它的输出将是一个字符串：

Three Guys Burger Spicy#2#Three guys burger tender, juicy, full of flavor, served with bbq sauce mixed with special sauce#Burger1.PNG#

我想用这些元素创建一个JavaScript数组：

['Three Guys Burger Spicy', 2, 'Three guys burger tender, juicy, full of flavor, served with bbq sauce mixed with special sauce', 'Burger1.PNG']

是否有预定义的函数要使用？你有解决办法吗？

Answer 1

您可以将字符串拆分为“#”：

var output = "#Three Guys Burger Spicy#2#Three guys burger tender, juicy, full of flavor, served with bbq sauce mixed with special sauce#Burger1.PNG#";

// Remove any trailing/leading hashes
output = output.replace(/^#/, "").replace(/#$/, "");

// Split on "#", then convert any numeric entries to numbers
var arr = output.split("#").map(item => !isNaN(Number(item)) ? Number(item) : item);
console.log(arr);

Answer 2

const str = 'Three Guys Burger Spicy#2#Three guys burger tender, juicy, full of flavor, served with bbq sauce mixed with special sauce#Burger1.PNG#';

const arr = str.split('#').filter(v => v);

console.log( arr );

Answer 3

一种简单得多的方法是将数组编码为JSON——这将生成您想要的结果，而无需任何额外的字符串构建和字符串解析。

echo json_encode($ajaxArray);

在接收到JSON时，JavaScript端需要做的就是解析JSON（通常使用JSON.parse（）），然后就有了一个JavaScript数组。

N. B.根据所显示的内容，似乎只期望从查询返回一行。如果是这样，您也可以缩短填充数组的代码：

if ($row = $req->fetch(PDO::FETCH_NUM)) {
    $ajaxArray = $row;
}

文件参考：

• https://www.php.net/manual/en/function.json-encode.php
• https://www.php.net/manual/en/pdostatement.fetch.php