使用JAXB解封

Question

<user>
  <id>123</id>
  <name>John Doe</name>
  <vaddresses>
    <address>
      <street>Street XYZ</street>
    </address>
    <address>
      <street>Street ABC</street>
    </address>
  </vaddresses>
</user>

我有这些课程：

• 用户

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "User", propOrder = {"id", "name", "addresses"})
public class User {

    @XmlElement
    private int id;

    @XmlElement
    private String name;

    @XmlElement
    private List<Address> addresses;

    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public List<Address> getAddresses() {
        return addresses;
    }

    public void setAddresses(List<Address> addresses) {
        this.addresses = addresses;
    }

• 地址

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "Address", propOrder = {"street"})
public class Address {

    @XmlElement
    private String street;

    public String getStreet() {
        return street;
    }

    public void setStreet(String street) {
        this.street = street;
    }
}

• 输出

User: 
    Id: 123
    Nome: John Doe
    Addresses: null

我如何解决这个问题？我是否可以使用一些JAXB注释？怎么做？还是需要创建某种类型的XmlAdapter？（我试过这个，但没有成功……)

Answer 1

您可以利用@XmlElementWrapper在集合周围添加分组元素：

@XmlElementWrapper(name="vaddresses")
@XmlElement(name="address")
private List<Address> addresses;

注

您添加的注释比必要的要多。JAXB是按异常配置的，所以您只需要注释希望XML表示不同于默认表示的地方。

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