正确应用封装

Question

我一直在研究封装的概念，发现了一些关于这个主题的不错的线索，比如这个和这个。但我还没能找到一个具体问题的答案。我将使用Swift中的一个示例。

假设你有一个RoadTrip类型的对象：

class RoadTrip() {
    private var duration: Double
    private var totalMiles: Double
    private var gallonsOfFuel: Double

    var averageMilesPerGallon: Double
}

现在让我们假设应用程序将计算AverageFileSpergallon，这是唯一的公共属性：

func calculateAverageMilePerGallon() -> Double {
    let mpg = totalMiles / gallonsOfFuel

    return mpg
}

每加仑平均英里数的计算是RoadTrip对象执行和更新其averageMilesPerGallon的私有方法，还是可以接受由单独实用程序类中的另一个方法执行计算，然后更新RoadTrip的averageMilesPerGallon属性对象是否使用将设置值的mutator方法？

编辑：这是我的一个类，包含我的应用程序的基本计算。我是根据我在iTunes上的斯坦福课程中学到的东西来处理这个问题的，但我开始想，在我的案例中，我应该把大部分内容转移到我的LiftEvent课程中：

infix operator ^^ { }
func ^^ (radix: Double, power: Double) -> Double {
    return Double(pow(Double(radix), Double(power)))
}

class CalculatorBrain: NSObject {
    var weightLifted: Double?
    var repetitions: Double?
    var oneRepMax: Double?
    let dataManager = LiftEventDataManager()

    func calculateOneRepMax(weightLifted: Double, repetitions: Int ) -> Double {
        let preferredFormulaID = UserDefaultsManager.sharedInstance.preferredFormula!
        let formulas = dataManager.fetchSelectableFormulas()
        let formulaName = formulas[preferredFormulaID].formulaName

        switch formulaName {
        case "Epley":
            oneRepMax = weightLifted * (1 + Double(repetitions)/30.0)
            return oneRepMax!
        case "Baechle":
            oneRepMax = weightLifted * (36/(37 - Double(repetitions)))
            return oneRepMax!
        case "Brzychi":
            oneRepMax = weightLifted * ( 1 + ( 0.033 * Double(repetitions)))
            return oneRepMax!
        case "Lander":
            oneRepMax = 100 * weightLifted / (101.3 - (2.67123 * Double(repetitions)))
            return oneRepMax!
        case "Lombardi":
            oneRepMax = weightLifted * (Double(repetitions) ^^ 0.10)
            return oneRepMax!
        case "Mayhew":
            oneRepMax = 100 * weightLifted / (52.2 + (41.9 * (2.71828 ^^ (-0.055 * Double(repetitions)))))
            return oneRepMax!
        case "O'Conner":
            oneRepMax = weightLifted * (1 + 0.025 * Double(repetithtml" target="_blank">ions))
            return oneRepMax!
        default:
            return 0.0
        }
    }


    private func calculatePercentOfWeight(maxWeight: Double, percent: Double) -> Double {
        return maxWeight * percent
    }

    func calculateWeightPercentages(maxWeight: String) -> [Int: Double] {
        let weightPercentages = [1.0, 0.95, 0.90, 0.85, 0.80, 0.75, 0.70, 0.65, 0.60, 0.55, 0.50, 0.45, 0.40, 0.35, 0.30, 0.25]

        var percentages = [Int: Double]()
        for percent in weightPercentages {
            let integerPercent = Int(percent * 100)
            percentages[integerPercent] = calculatePercentOfWeight(Double(maxWeight)!, percent: percent)
        }
        return percentages
    }

    func convertBetweenUnits(fromUnit: Int, toUnit: Int, value: Double) -> Double {
        let units = dataManager.fetchUnits()
        let from = units[fromUnit].conversionRatio as Double
        let to = units[toUnit].conversionRatio as Double
        let result = Double(value * to / from)
        return result
    }
}

Answer 1

我认为这是计算属性的理想用例：

class RoadTrip {
    private let duration: Double
    private let totalMiles: Double
    private let gallonsOfFuel: Double

    private var averageMilesPerGallon: Double {
        return totalMiles / gallonsOfFuel
    }
}