在android中通过http post方法发送json对象

Question

它不是重复的。所提供的链接是旧的。“HTTP客户端”已在api23中删除

我想发送json对象：

{"emailId":"[e-mail]","address":"Naya bans","city":"Noida","pincode":"201301","account_number":"91123546374208","bank_name":"Axis Bank","branch_name":"91123546374208","ifsc_code":"UTI0000879"}

到URL：

http://10digimr.mobimedia.in/api/mobile_retailer/update_profile怎么做？通过post方法？

 POST /api/mobile_retailer/update_profile

{"emailId","address"}

{"emailId":"[e-mail]","address":"Naya bans","city":"Noida","pincode":"201301","account_number":"91123546374208","bank_name":"Axis Bank","branch_name":"91123546374208","ifsc_code":"UTI0000879"}

回应：

{"message":"Mail Send","data":true,"status":200}

Answer 1

定义一个类Asynct并在oncreate方法中调用它，使用：

AsyncT asyncT = new AsyncT();
asyncT.execute();

类定义：

class AsyncT extends AsyncTask<Void,Void,Void>{

        @Override
        protected Void doInBackground(Void... params) {

            try {
                URL url = new URL(""); //Enter URL here
                HttpURLConnection httpURLConnection = (HttpURLConnection)url.openConnection();
                httpURLConnection.setDoOutput(true);
                httpURLConnection.setRequestMethod("POST"); // here you are telling that it is a POST request, which can be changed into "PUT", "GET", "DELETE" etc.
                httpURLConnection.setRequestProperty("Content-Type", "application/json"); // here you are setting the `Content-Type` for the data you are sending which is `application/json`
                httpURLConnection.connect();

                JSONObject jsonObject = new JSONObject();
                jsonObject.put("para_1", "arg_1");

                DataOutputStream wr = new DataOutputStream(httpURLConnection.getOutputStream());
                wr.writeBytes(jsonObject.toString());
                wr.flush();
                wr.close();

            } catch (MalformedURLException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            } catch (JSONException e) {
                e.printStackTrace();
            }

            return null;
        }


    }