语法错误：“print”调用中缺少括号[重复]

Question

我一直试图搜集一些推特的数据，但每次运行此代码时，都会出现错误：调用“print”时缺少括号。

有人能帮我解决这个问题吗？

感谢您的时间：）

"""
Use Twitter API to grab user information from list of organizations; 
export text file
Uses Twython module to access Twitter API
"""

import sys
import string
import simplejson
from twython import Twython

#WE WILL USE THE VARIABLES DAY, MONTH, AND YEAR FOR OUR OUTPUT FILE NAME
import datetime
now = datetime.datetime.now()
day=int(now.day)
month=int(now.month)
year=int(now.year)


#FOR OAUTH AUTHENTICATION -- NEEDED TO ACCESS THE TWITTER API
t = Twython(app_key='APP_KEY', #REPLACE 'APP_KEY' WITH YOUR APP KEY, ETC., IN THE NEXT 4 LINES
    app_secret='APP_SECRET',
    oauth_token='OAUTH_TOKEN',
    oauth_token_secret='OAUTH_TOKEN_SECRET')

#REPLACE WITH YOUR LIST OF TWITTER USER IDS
ids = "4816,9715012,13023422, 13393052,  14226882,  14235041, 14292458, 14335586, 14730894,\
    15029174, 15474846, 15634728, 15689319, 15782399, 15946841, 16116519, 16148677, 16223542,\
    16315120, 16566133, 16686673, 16801671, 41900627, 42645839, 42731742, 44157002, 44988185,\
    48073289, 48827616, 49702654, 50310311, 50361094,"

#ACCESS THE LOOKUP_USER METHOD OF THE TWITTER API -- GRAB INFO ON UP TO 100 IDS WITH EACH API CALL
#THE VARIABLE USERS IS A JSON FILE WITH DATA ON THE 32 TWITTER USERS LISTED ABOVE
users = t.lookup_user(user_id = ids)

#NAME OUR OUTPUT FILE - %i WILL BE REPLACED BY CURRENT MONTH, DAY, AND YEAR
outfn = "twitter_user_data_%i.%i.%i.txt" % (now.month, now.day, now.year)

#NAMES FOR HEADER ROW IN OUTPUT FILE
fields = "id screen_name name created_at url followers_count friends_count statuses_count \
    favourites_count listed_count \
    contributors_enabled description protected location lang expanded_url".split()

#INITIALIZE OUTPUT FILE AND WRITE HEADER ROW
outfp = open(outfn, "w")
outfp.write(string.join(fields, "\t") + "\n")  # header

#THE VARIABLE 'USERS' CONTAINS INFORMATION OF THE 32 TWITTER USER IDS LISTED ABOVE
#THIS BLOCK WILL LOOP OVER EACH OF THESE IDS, CREATE VARIABLES, AND OUTPUT TO FILE
for entry in users:
    #CREATE EMPTY DICTIONARY
    r = {}
    for f in fields:
        r[f] = ""
    #ASSIGN VALUE OF 'ID' FIELD IN JSON TO 'ID' FIELD IN OUR DICTIONARY
    r['id'] = entry['id']
    #SAME WITH 'SCREEN_NAME' HERE, AND FOR REST OF THE VARIABLES
    r['screen_name'] = entry['screen_name']
    r['name'] = entry['name']
    r['created_at'] = entry['created_at']
    r['url'] = entry['url']
    r['followers_count'] = entry['followers_count']
    r['friends_count'] = entry['friends_count']
    r['statuses_count'] = entry['statuses_count']
    r['favourites_count'] = entry['favourites_count']
    r['listed_count'] = entry['listed_count']
    r['contributors_enabled'] = entry['contributors_enabled']
    r['description'] = entry['description']
    r['protected'] = entry['protected']
    r['location'] = entry['location']
    r['lang'] = entry['lang']
    #NOT EVERY ID WILL HAVE A 'URL' KEY, SO CHECK FOR ITS EXISTENCE WITH IF CLAUSE
    if 'url' in entry['entities']:
        r['expanded_url'] = entry['entities']['url']['urls'][0]['expanded_url']
    else:
        r['expanded_url'] = ''
    print r
    #CREATE EMPTY LIST
    lst = []
    #ADD DATA FOR EACH VARIABLE
    for f in fields:
        lst.append(unicode(r[f]).replace("\/", "/"))
    #WRITE ROW WITH DATA IN LIST
    outfp.write(string.join(lst, "\t").encode("utf-8") + "\n")

outfp.close()

Answer 1

您只需要将pranethesis添加到您的print statmetnt以将其转换为函数，就像错误所说的那样：

print expression -> print(expression)

在Python 2中，print是一个语句，但在Python 3中，print是一个函数。因此，您也可以使用Python 2运行您的代码。print（表达式）向后兼容Python 2。

还有，你为什么把所有的评论都大写？真烦人。您的代码还以多种方式违反了PEP 8。找一个像PyCharm这样的编辑器（免费），它可以自动检测这样的错误。

• 您在评论和评论之间没有留下空格

Answer 2

看起来您正在尝试在Python 3中运行Python 2代码，其中打印是函数和必需的括号：

print(foo)

Answer 3

您似乎正在使用python 3。x、 然而，您在这里运行的代码是python 2。x代码。解决此问题的两种方法：

• 在Python的网站上下载python 2. x并使用它来运行您的脚本
• 在末尾的print调用周围添加括号，将print r替换为print（r）（并继续使用python 3）

但如今，越来越多的python程序员正在使用python 3，官方的python wiki声明如下：

Python 2. x是传统，Python 3. x是语言的现在和未来

如果我是你，我会选择第二个选项并继续使用python 3。