将XML数据附加到ArrayList

Question

我已经创建了一个XML解析器来将XML文件中的信息检索到java，然后我尝试将这些数据存储到ArrayList中，以便将ArrayList用于我的方法。当我打印出来时，它似乎工作得很好。然而，由于某种原因，我得到了一个名为getAllRoutes的方法，它返回了错误的路由数

Answer 1

如果这对Khaled有帮助，请告诉我。

尝试以下操作：

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathExpression;
import javax.xml.xpath.XPathFactory;
import javax.xml.xpath.XPathExpressionException;

import org.w3c.dom.Document;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;

import java.util.Iterator;
import java.util.NoSuchElementException;
import java.util.List;
import java.util.ArrayList;
class Main {
  public static Iterable<Node> iterable(final NodeList nodeList) {
    return () -> new Iterator<Node>() {

        private int index = 0;

        @Override
        public boolean hasNext() {
            return index < nodeList.getLength();
        }

        @Override
        public Node next() {
            if (!hasNext())
                throw new NoSuchElementException();
            return nodeList.item(index++); 
        }
    };
  }
  private static List<String> evaluateXPath(Document document, String xpathExpression)
  {
        // Create XPathFactory object
        XPathFactory xpathFactory = XPathFactory.newInstance();

        // Create XPath object
        XPath xpath = xpathFactory.newXPath();

        List<String> values = new ArrayList<>();
        try
        {
            // Create XPathExpression object
            XPathExpression expr = xpath.compile(xpathExpression);

            // Evaluate expression result on XML document
            NodeList nodes = (NodeList) expr.evaluate(document, XPathConstants.NODESET);

            for (int i = 0; i < nodes.getLength(); i++) {
                values.add(nodes.item(i).getNodeValue());
            }

        } catch (XPathExpressionException e) {
            e.printStackTrace();
        }
        return values;
    }
  public static void main(String[] args) throws Exception {
        //Build DOM

        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        factory.setNamespaceAware(true); // never forget this!
        DocumentBuilder builder = factory.newDocumentBuilder();
        Document doc = builder.parse("data.xml");

        //Create XPath

        XPathFactory xpathfactory = XPathFactory.newInstance();
        XPath xpath = xpathfactory.newXPath();
        String xpathRoot = "//Routes/Route";
        XPathExpression expr = xpath.compile(xpathRoot);
        int i = 0;
        for (Node n : iterable((NodeList) expr.evaluate(doc, XPathConstants.NODESET))) {
          i++;
          String xpe2 = String.format("%s[%d]/%s/text()", xpathRoot, i, "FlightNumber");
          System.out.println("FxPe: " + xpe2);
          System.out.println("Flight Number: " + evaluateXPath(doc, xpe2).get(0));
           for (Node n2 : iterable(n.getChildNodes())) {
              System.out.println(n2.getTextContent());
           }

        }
  }
}

在此处查看它的实际操作

有用的链接：

>

1： 遍历节点列表

2： XPath备忘单

3： Java XPath示例a和b

4： 节点列表Java文档

5：节点Java文档

我会说。I您的代码：Route r=new Route（） 应该在if语句<代码>if（c.getNodeName（））中。等于（“路由”））注释掉的add位于正确的位置-另一个位置错误。

Answer 2

请移动

routes.add(r);

里面

if (c.getNodeName().equals("Route")) {