用特定语法将Java对象转换为JSON

Question

public class User{
    private Long id;
    private String firstName;
}

{
    "inputFields":[
        {
            "name":"id",
            "value":"123"
        },
        {
            "name":"firstName",
            "value":"George"
        }
    ]
}

尝试使用Jackson，但它看起来不提供这样的序列化。

Answer 1

Jackson可以使用自定义序列化程序，在此程序中可以控制输出的生成。以下是执行此操作的步骤：

注释POJO以使用自定义序列化程序

@JsonSerialize(using = CustomSerializer.class)
static class User{
    public Long id;
    public String firstName;

    public User(Long id, String firstName) {
        this.id = id;
        this.firstName = firstName;
    }

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

    public String getFirstName() {
        return firstName;
    }

    public void setFirstName(String firstName) {
        this.firstName = firstName;
    }
}

声明序列化程序

static class CustomSerializer extends JsonSerializer{

    @Override
    public void serialize(Object value, JsonGenerator jgen, SerializerProvider serializers) throws IOException, JsonProcessingException {
        jgen.writeStartObject();
        jgen.writeArrayFieldStart("inputFields");

        Field[] fields = value.getClass().getDeclaredFields();

        for (Field field : fields) {
            try {
                field.setAccessible(true);
                jgen.writeStartObject();
                jgen.writeObjectField("name", field.getName());
                jgen.writeObjectField("value", field.get(value));
                jgen.writeEndObject();
            } catch (IllegalArgumentException | IllegalAccessException e) {
                e.printStackTrace();
            }

        }

        jgen.writeEndArray();
        jgen.writeEndObject();
    }
}

public static void main(String[] args) throws JsonProcessingException {
    User user = new User(1L, "Mike");
    ObjectMapper om = new ObjectMapper();
    om.writeValueAsString(user);
    System.out.println(om.writeValueAsString(user));
}

{"inputFields":[{"name":"id","value":1},{"name":"firstName","value":"Mike"}]}